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mel-nik [20]
1 year ago
11

Given P equals $11260, T equals six years, and R equals 7.5% compounded weekly. Use the correct compound interest formula to cal

culate to the nearest cent the value of A.
Mathematics
1 answer:
Dmitrij [34]1 year ago
3 0

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

where

A = total amount in the account at the end of t years

r represents the interest rate

n represents the periodic interval at which it was compounded

p represents the principal or initial amount deposited

From the information given,

P = 11260

t = 6

r = 7.5/100 = 0.075

n = 52(Assuming the number of weeks in a year is 52 and it would be compounded 52 times in a year)

Thus, we have

A = 11260(1 + 0.075/52)^52*6

A = 11260(1 + 0.075/52)^312

A = 17653.5

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Graph the following piecewise function:
zhenek [66]
Check the picture below.

notice the solid circle at -4 and 3, since it includes those points.

also notice the dashed line, though the lines keeps on going those ways, is not included in the piece-wise, since it's not part fo the domain or constraints.

5 0
3 years ago
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
Complete the square for 3x^2-12x=9
larisa [96]

Answer:

The solutions are -0.65 and 4.65.

Step-by-step explanation:

3x^2 - 12x = 9

Divide both sides by 3

x^2 - 4x = 3

To make a square with "x^2 - 4x", you need to have a "+ 4" after it so it can be simplified as (x-2)^2.  So add 4 to both sides.

x^2 - 4x + 4 = 7

(x-2)^2 = 7

x - 2 = (square root) of 7

x = 2 (+/-) (square root) of 7.

x = {-0.65, 4.65}

The solutions are -0.65 and 4.65.

hope this helps:)sorry if it doesnt

8 0
3 years ago
Read 2 more answers
URGENT URGENT helppps plz
Murljashka [212]

Answer:

1) Bigger sector = 168.8pi

1) Smaller sector = 56.3pi

2) Bigger sector = 529.9

3) Smaller sector = 176.6

Step-by-step explanation:

1) Bigger sector =  \frac{270}{360}×pi×15×15

                          = 168.75pi

1) Smaller sector = \frac{360-270}{360}×pi×15×15

                             = \frac{90}{360}×pi×15×15

                             = 56.25pi

2) Bigger sector =  \frac{270}{360}×3.14×15×15

                           = 529.875

2) Smaller sector = \frac{360-270}{360}×3.14×15×15

                             = \frac{90}{360}×3.14×15×15

                             = 176.625

6 0
3 years ago
Takashi ran 200 yards in 40 seconds Ana ran 150 yards in 25 seconds can u tell who runs faster without rewriting the rates expla
Marina86 [1]
150 is smaller than 200 so 25 is smaller than 40, but 25, in perspective to the numbers, is much smaller than 40. Ana is faster.

Check:

Takashi: 200 divided by 400 equals 5 yd/sec
Ana: 150 divided by 25 equals 6 yd/sec
7 0
3 years ago
Read 2 more answers
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