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grigory [225]
3 years ago
12

Using v= Iwh, what is an expression for the volume of the following rectangular prism

Mathematics
2 answers:
joja [24]3 years ago
4 0

Answer:

lwh

Step-by-step explanation:

no picture was provided

barxatty [35]3 years ago
3 0

Alrighty, so...

We know that the volume of a prism is equal to its length times its width times its height  <em> </em><em>( V= L * W *H )</em>

For example, if we were given a problem in which we are given each of those variables, all we have left to do is plug each one of them into the equation above!

Solving for your answer would hypothetically look like this:

V=\frac{d-2}{3(d-3)} × \frac{4}{d-4} × \frac{(d-3)}{(d-2)} = \frac{4}{3(d-4)} = \frac{4}{3d-12}

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The graph of the function f(x) = (x + 2)(x - 4) is shown.
hoa [83]

Answer:

B)   All real values of 'x' where -2 < x< 4

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function f(x) = (x +2 ) ( x-4)

                  (x+2)(x-4) =0

          ⇒  x +2 =0 and x-4=0

          ⇒  x =-2   and x=4

From graph

       Given parabola lies between the x=-2 and x =4

∴ All real values of 'x' lies between x=-2 and x =4

 All real values of 'x' lies -2 < x< 4

6 0
3 years ago
I'm BEGGING you. plz help. I will mark you brainliest. I have an image attached with the question.
mariarad [96]

Answer:

start by mulitplying ten 5 times so 10x10x10x10x10=100,000. then multiply 100,000x3.8=380,000. and then times 300 so your ancwer is 114,000,000

Step-by-step explanation:hope it helps

3 0
3 years ago
Which expressions are polynomials?
AlekseyPX

one of those questions are polynomials and the one that is a polynomial is obviously the answer and that would be the third one


5 0
3 years ago
Read 2 more answers
Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
HELP !!!! can someone help me please how can i use the vertex formula to find this equation for this graph ?
DedPeter [7]
Based on that table of values, we know the highest point(vertex) is at 0.9, 5.9

we can also use just one another point... say 1.4, 4.6

\bf \qquad \textit{parabola vertex form}\\\\&#10;\begin{array}{llll}&#10;y=a(x-{{ h}})^2+{{ k}}&#10;\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\&#10;-------------------------------\\\\

\bf \begin{cases}&#10;h=0.9\\&#10;k=5.9&#10;\end{cases}\implies y=a(x-0.9)^2+5.9&#10;\\\\\\&#10;\begin{cases}&#10;\textit{another point}\\&#10;x=1.4\\&#10;y=4.6&#10;\end{cases}\implies 4.6=a(1.4-0.9)^2+5.9&#10;\\\\\\&#10;4.6=a(0.5)^2+5.9\implies 4.6-5.9=a(0.5)^2\implies -1.3=a(0.5)^2&#10;\\\\\\&#10;\cfrac{-1.3}{0.5^2}=a\implies -5.2=a&#10;\\\\\\&#10;thus\qquad \qquad \boxed{y=-5.2(x-0.9)^2+5.9}
5 0
3 years ago
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