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2 years ago

HELP ME W MY MATH IM BEGGINGM

Mathematics

1 answer:

wel2 years ago

3 0

Answer:

Year 1: 164.87

Year 2: 169.88

Year 5: 185.86

Step-by-step explanation:

She is earning 3% interest per year that compounds once yearly.

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PLEASE HELP!

leva [86]

Answer:

B. 56°

Step-by-step explanation:

We are given that m∠R is 66° and m∠T is 122°.

We can apply the supplementary rule since ∠S and ∠T are a linear pair. So, we can use ∠T to find ∠S through 180° - 122° = 58°.

Now, we can use ∠R and ∠S to find ∠Q.

66° + 58° = 124°

180° - 124° = 56°

8 0

2 years ago

What is the sample space for the event of flipping a coin and then spinning a four-part spinner, numbered 1, 2, 3, 4?

Anastasy [175]

Answer:it is 2 since it include3s all possible answers for both heads & tails.

Step-by-step explanation:

you can get a H1-4 & a T1-4 since you have 4 parts one the spinner & 2 things on a coin (Heads & tails) you can just times 4*2 & know that you have 8 possible answers.

8 0

2 years ago

What is the approximate area of the circle shown below? ???? Help ???

PIT_PIT [208]

Answer:

D. 1662 cm

Step-by-step explanation:

A=πr2=π•23≈1661.90251cm²

which is 1661.9

but of course you have to round up for 1662 cm :)

7 0

2 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are without replacement.

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

2 years ago

If the endpoint is (-5,8) and the midpoint is (10,-9) what would the other endpoint be

netineya [11]

Answer:

thats a great question

Step-by-step explanation:

6 0

3 years ago