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lisov135 [29]
3 years ago
7

How would start to solve: log-4x-log4=1

Mathematics
1 answer:
liubo4ka [24]3 years ago
4 0

log -4x-log4=1

when subtracting logs of the same base, you divide)

log (-4x/4)=1

log (-x) = 1

inverse of log is take it to the power of 10

-x = 10^1

-x = 10

divide by -1

x =-10

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5 0
3 years ago
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Need some help with this one please
Airida [17]

Answer: Choice A

y = (-3/4)(x + 4) + 6

=====================================================

Let's go through the answer choices

  • Choice A is something we'll come back to
  • Choice B is false because the line does not go uphill as we move from left to right. The graphed line has a negative slope, which contradicts what choice B is saying.
  • Choice C is false for similar reasons as choice B. The slope should be negative.
  • Choice D has a negative slope, but the y intercept is wrong. The y intercept should be 3. So choice D is false as well.

We've eliminated choices B through D.

Choice A must be the answer through process of elimination.

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Here's an alternative method:

If we started at a point like (0,3) and move to (4,0), note how the slope is -3/4

This is because we've moved down 3 units and to the right 4 units.

m = slope = rise/run = -3/4

We can also use the slope formula m = (y2-y1)/(x2-x1) to see this.

Then we pick on a point that is on the diagonal line. It could be any point really, but the point your teacher used for choice A is (x1,y1) = (-4,6)

So,

y - y1 = m(x - x1)

y - 6 = (-3/4)(x - (-4))

y - 6 = (-3/4)(x + 4)

y = (-3/4)(x + 4) + 6

7 0
4 years ago
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Answer:

don't get what

Step-by-step explanation:

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3 0
3 years ago
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natima [27]

Answer:

x= 5/8

Step-by-step explanation:

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3 years ago
What is an equation of the line that passes through the points (6, -4)(6,−4) and (1, 6)(1,6)?
NARA [144]

Answer:

Rhe equation would be y= -2x+8

3 0
3 years ago
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