Hope this is straightforward.
(c+4/c^2+5c+6)/(3c^2+12c/2c^2+5c-3)= (c+4)/(c^2+5c+6) Multiplied by (2c^2+5c-3)/3c^2+12c= 2c^3+5c^2-3c+8c^2+20c-12/3c^4+12c^3+15c^3+60c^2+18c^2+72= 2c^3+13c^2+17c-12/3c^4+27c^3+78c^2+72c
Answer:
(d) The parabola g(x) will open in the same direction of f(x), and the parabola will be wider than f(x).
Step-by-step explanation:
We assume you intend ...
f(x) = equation of a parabola
g(x) = 2/3·f(x)
Multiplying a function by a factor of 2/3 will cause it to be compressed vertically to 2/3 of its original height. When the function is a parabola, this has the effect of making it appear wider than before the compression.
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The compression factor is positive, so points on the graph remain on the same side of the x-axis. The direction in which the graph opens is not changed.
The attachment shows parabolas that open upward and downward, along with the transformed version.
The number that goes into 15 and 25 is 5. So after you factor this it would be 5(3a+5b).