10. A minute hand will clearly turn a total of 360° in an hour. How many minutes will it take for the minute hand

Kevin has just purchased a small rectangular fish tank that holds 904.5 milliliters of water. The tank has a length of 15 cm and

Nitella [24]

Answer:

A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?

Step-by-step explanation:

A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?

5 0

3 years ago

Solve using substitutuon6x+7y=8. y=-2x

belka [17]

You plug in 2x in the equation for y. Since y =2x. 6x+7(2x)=8 6x+14x=8. 20x=8. X=8/20. X=2/5. Is your final answer

4 0

3 years ago

Let S be the surface defined by x 2 + 2y 3 + 3z 4 = 6. Let T be the surface defined parametrically by r(u, v) = (1+ln u, 2e v+u−

aleksandrvk [35]

The tangent to $C$ through (1, 1, 1) must be perpendicular to the normal vectors to the surfaces $S$ and $T$ at that point.

Let $f(x,y,z)=x^2+2y^3+3z^4$ . Then $S$ is the level curve $f(x,y,z)=6$ . Recall that the gradient vector is perpendicular to level curves; we have

$\nabla f(x,y,z)=(2x,6y,12z^2)$

so that the gradient of $f$ at (1, 1, 1) is

$\nabla f(1,1,1)=(2,6,12)$

For the surface $T$ , we have

$\begin{cases}1+\ln u=1\\2e^v+u-2=1\\uv+1=1\end{cases}\implies u=1,v=0$

so that $\vec r(1,0)=(1,1,1)$ . We can obtain a vector normal to $T$ by taking the cross product of the partial derivatives of $\vec r(u,v)$ , and evaluating that product for $u=1,v=0$ :

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left(u-2ve^v,-1,\dfrac{2e^v}u\right)$

$\left(\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right)(1,0)=(1,-1,2)$

Now take the cross product of the two normal vectors to $S$ and $T$ :

$(2,6,12)\times(1,-1,2)=(24,8,-8)$

The direction of vector (24, 8, -8) is the direction of the tangent line to $C$ at (1, 1, 1). We can capture all points on the line containing this vector by scaling it by $t\in\Bbb R$ . Then adding (1, 1, 1) shifts this line to the point of tangency on $C$ . So the tangent line has equation

$\vec\ell(t)=(1,1,1)+t(24,8,-8)=(1+24t,1+8t,1-8t)$

7 0

3 years ago

there are 7 people in his family if each burger weighs 3/4 of a pound how much ground beef should john buy

Nataliya [291]

If the ground beef is in pounds, it would be 5.25 lbs of ground beef.

We would get this answer by converting 3/4 into a decimal, .75. Then we multiply .75 by 7 (the number of people).

((This is if the amount of ground beef is in pounds, I'm not sure what it would be if it wasn't))

7 0

3 years ago

The exam scores (out of 100 points) for all students taking an introductory Statistics course are used to construct the followin

ella [17]

Answer:

The inter quartile range is 55

Step-by-step explanation:

Interquartile range:-

Definition:-

The inter quartile range is the difference between the upper (Q3) and lower(Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest.

Interquartile range = higher quartile - lower quartile

given data 50.25.80.10

write the ascending order 10 25 50 80

Step:-1

Median:- The median is obtained by first arranging the data in ascending or descending order and applying the following rule.

If the number of observations is odd, then the median is

$({\frac{n+1}{2} })^{th}$ observations

Step2:-

The median is obtained by first arranging the data in ascending or descending order and applying the following rule.

If the number of observations is even, then the median is $({\frac{n}{2} })^{th}$

$({\frac{n+1}{2} })^{th}$

In given data the number of observations is '4'(even)

If the number of observations is even, then the median is $({\frac{n}{2} })^{th}$

$({\frac{n+1}{2} })^{th}$

median is $({\frac{4}{2} })^{th}$ is 2 observations and $({\frac{4+1}{2} })^{th}$ is 2.5 observations.

so we have to select average of these two observations.

therefore the median is '3' observation

median of the given data = 50

Step:3

Interquartile range = higher quartile - lower quartile

= 80-25

=55

3 0

3 years ago