Answer is 64 and a factor is 6/4 .
Well, you have to ask the question first.
Answer:
14
Step-by-step explanation:
so the pattern is they add 2 then they add 4 then they add 8 then the add 16 basically they are double the number being added each number so the missing number is 14
<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
Answer:
- c = -4.5
- z = 20
- x = -12
- a = -4/7
Step-by-step explanation:
A way to do this that will always work is ...
- eliminate parenthses and collect terms
- subtract any constants from the left side
- subtract any variable terms from the right side
- divide by the coefficient of the variable
1.
- 8c -11 -6c = -2
- 2c -11 = -2
- 2c = 9
- c = 4.5
2.
- 3z +4 -2z -9 = 15
- z -5 = 15
- z = 20
3.
- 12 -4x +18 = 36 +4x +18 -6x
- 30 -4x = 54 -2x
- -4x = 24 -2x
- -2x = 24
- x = -12
4.
- 36a -9a -5 = 6a -17
- 27a -5 = 6a -17
- 27a = 6a -12
- 21a = -12
- a = -12/21 = -4/7