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valentina_108 [34]
3 years ago
15

Marcus is rewriting a polynomial by combining like terms. Which terms does he still need to combine to finish rewriting the poly

nomial?
-3mn^3 - 4n^4 + 2mn - 6n - 5mn^3 - 6m^3n
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:-3mn^3 and -5mn^3

Step-by-step explanation:

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Please help asap 25 pts
Alchen [17]
The answer to you question is c
5 0
3 years ago
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Select the description of the graph created by the equation 3x2 - 6x + 4y - 9 = 0.
max2010maxim [7]

Answer:

C

Step-by-step explanation:

Parabola with a vertex at (1, 3) opening downward.

5 0
2 years ago
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I don't understand how to do find x and y, please help? thank yous.
pav-90 [236]

#8) There are THREE right-angle (90°) TRIANGLES.

The "big" triangle has legs "x" and "no designation - <em>so lets call it Z" </em>and hypotenuse "4+5"<em> = 9</em>

The "left" triangle has legs "4" and "y" and hypotenuse "x"

The "right" triangle has legs "5" and "y" and hypotenuse "no designation - <em>which we named Z</em>"

Now, you can create a system of equations - you have three unknown variables and can create an equation for each triangle using the Pythagorean Theorem.

Big: x² + Z² = 9² → x² + Z² = 81

Left: 4² + y² = x² → 16 + y² = x² → 16 = x² - y² → x² - y² = 16

Right: 5² + y² = Z² → 25 + y² = Z²

Next, let's eliminate Z by using substitution....use the Right equation to plug Z² into the Big equation to create a NEW Big equation.

NEW Big: x² + (25 + y² ) = 81 → x² + y² = 81 - 25 → x² + y² = 56

Now, we have two unknown variables (x and y) and two equations (NEW Big and Left). Solve the system using any method. <em>I am going to solve using the elimination method)</em>

NEW Big: x² + y² = 56

+ Left: <u>x² - y² = 16</u>

2x² = 72 <em>added the NEW Big and Left equations</em>

x² = 36 <em>divided both sides by 2</em>

x = 6 <em>took square root of both sides (NOTE: -6 is disregarded because we are solving for a length, which cannot be negative) </em>

The last step is to plug the "x" value (<em>that we just solved for)</em> into one of the equations to solve for "y". <em>I am choosing to use the Left equation.</em>

<em> </em>x² - y² = 16

36 - y² = 16<em> </em>

- y² = 16 - 36

- y² = -20

y² = 20

y = √20

y = 2√5

Answer: x = 6, y = 2√5

Try #9 on your own and then check your answers below:

Big: Z² + x² = 12², Left: 3² + y² = Z², Right: y² + 9² = x²

Answer: x = 6√3, y = 3√3

7 0
2 years ago
Reflection Over Parallel Lines Please complete the attached reflection. Thanks!
Allushta [10]

Answer: A(3, -5)

B(6, -2)

C(9, -2)

Step-by-step explanation:

If we have a point (x, y), and we do a reflection over the axis y = a, then the only thing that will change in our point is the value of x.

Now, the distance between x and a must remain constant before and after the reflection.

so if x - a = d

then the new position of the point will be:

(a - d, y) = (2a - x, y).

I will use that relationship for the 3 points

A)

We start with the point (1, -5)

The reflection over y = -1 leaves.

The distance between 1 and -1 is = 1 - (-1) = 2.

Then the new point is (-1 - 2, -5) = (-3, -5)

Now we do a reflection over y = 1, so D = -3 - 1 = -2

Then the new point is:

A = (1 -(-2), -5) = (3, -5)

B) (2, -2)

Reflection over y = -1.

distance, d = 2 - (-1) = 3

the point is (-1 - 3, -2) = (-4, -2)

Now, a reflection over y = 1.

The distance is D = -4 - 1 = -5

The new point is (1 - (-5), 2) = (6, -2)

C) (5, -2)

reflection over y = -1

Distance: D = 5 - ( - 1) = 6

New point: (-1 - 6, -2) = (-7, -2)

Reflection over y = 1.

Distance D = -7 - 1 = -8

New point ( 1 - (-8), -2) = (9, -2)

4 0
3 years ago
Would this be c ? I’m not sure if you add the 2 (z) which will then make it 2z but from there I don’t know we’re to go
attashe74 [19]

Answer: yes it would be C because deconstructed, it’s z + z + 6 which is the same as the original statement

Step-by-step explanation:

4 0
3 years ago
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