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2 years ago

7

Solve the formula for the indicated variable:

1 answer:

Mars2501 [29]2 years ago

5 0

ANSWER : v1 = at + v0
multiply t to both sides then isolate v1 by adding v0 on both sides

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To find the equation of a line, we need the slope of the line and a point on the line. Since we are requested to find the equati

murzikaleks [220]

Answer:

$x-4y+4=0$

$f(x)=\sqrt x$ and x=4

Step-by-step explanation:

We are given that a curve

$y=\sqrt x$

We have to find the equation of tangent at point (4,2) on the given curve.

Let y=f(x)

Differentiate w.r.t x

$f'(x)=\frac{dy}{dx}=\frac{1}{2\sqrt x}$

By using the formula $\frac{d(\sqrt x)}{dx}=\frac{1}{2\sqrt x}$

Substitute x=4

Slope of tangent

$m=f'(x)=\frac{1}{2\sqrt 4}=\frac{1}{2\times 2}=\frac{1}{4}$

In given question

$m=\lim_{x\rightarrow a}\frac{f(x)-f(a)}{x-a}$

$\frac{1}{4}=\lim_{x\rightarrow 4}\frac{f(x)-f(4)}{x-4}$

By comparing we get a=4

Point-slope form

$y-y_1=m(x-x_1)$

Using the formula

The equation of tangent at point (4,2)

$y-2=\frac{1}{4}(x-4)$

$4y-8=x-4$

$x-4y-4+8=0$

$x-4y+4=0$

8 0

3 years ago

X = ?????? Geometry

adelina 88 [10]

Answer:

$\boxed{x^2 = 16}$

Step-by-step explanation:

Using Tangent Secant theorem:

(x)² = (2)(2+6)

x² = 2(8)

x² = 16

7 0

3 years ago

What is the domain of the function represented in the graph?

alisha [4.7K]

Answer:

0-t-14

Step-by-step explanation:

Its the first one I don't want to type

5 0

3 years ago

1/2 x + 2 = 1/6 x - 1 =

aksik [14]

Step-by-step explanation:

1/2x+2−1/6x=1/6x−1−1/6x

1/3x+2=−1

1/3x+2−2=−1−2

1/3x=−3

3*(1/3x)=(3)*(−3)

x=−9 <- ANSWER

3 0

3 years ago

Cos 4θ − cos 2θ = sin θ

hichkok12 [17]

$cos(4\theta) - cos(2\theta) = sin(\theta)$
$-2sin(\frac{4\theta + 2\theta}{2})sin(\frac{4\theta - 2\theta}{2}) = sin(\theta)$
$-2sin(\frac{6\theta}{2}sin\frac{2\theta}{2}) = sin(\theta)$
$-2sin(3\theta)sin(\theta) = sin(\theta)$
$\frac{-2sin(3\theta)sin(\theta)}{-2sin(\theta)} = \frac{sin(\theta)}{-2sin(\theta)}$
$sin(3\theta) = -\frac{1}{2}$
$sin^{-1}[sin(3\theta)] = sin^{-1}(-\frac{1}{2})$
$3\theta = -30$
$\frac{3\theta}{3} = \frac{-30}{3}$
$\theta = -10$

7 0

2 years ago