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2 years ago

Which applies the power of a product rule to simplify (5t)3

Mathematics

2 answers:

Eduardwww [97]2 years ago

8 0

Answers the 3 one

Step-by-step explanation:

larisa86 [58]2 years ago

3 0

Answer:

Step-by-step explanation:

$(5t)^{3} = 5^{3}*t^{3}\\\\=125t^{3}$

Hint:

$(xy)^{m}=x^{m}*y^{m}$

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What is the measurement of the longest line segment in a right rectangular prism that is 26 inches long, 2 inches wide, and 2 in

EastWind [94]

Answer:

$6\sqrt{19} \approx 26.153$ inches.

Step-by-step explanation:

The longest line segment in a right rectangular prism is the diagonal that connects two opposite vertices. On the first diagram attached, the green line segment connecting A and G is one such diagonals. The goal is to find the length of segment $\mathsf{AG}$ .

In this diagram (not to scale,) $\mathsf{AB} = 26$ (length of prism,) $\mathsf{AC} = 2$ (width of prism,) $\mathsf{AE} = 2$ (height of prism.)

Pythagorean Theorem can help find the length of $\mathsf{AG}$ , one of the longest line segments in this prism. However, note that this theorem is intended for right triangles in 2D, not the diagonal in a 3D prism. The workaround is to simply apply this theorem on two different right triangles.

Start by finding the length of line segment $\mathsf{AD}$ . That's the black dotted line in the diagram. In right triangle $\triangle\mathsf{ABD}$ (second diagram,)

Segment $\mathsf{AD}$ is the hypotenuse.
One of the legs of $\triangle\mathsf{ABD}$ is $\mathsf{AB}$ . The length of $\mathsf{AB}$ is $26$ , same as the length of this prism.
Segment $\mathsf{BD}$ is the other leg of this triangle. The length of $\mathsf{BD}$ is $2$ , same as the width of this prism.

Apply the Pythagorean Theorem to right triangle $\triangle\mathsf{ABD}$ to find the length of $\mathsf{AB}$ , the hypotenuse of this triangle:

$\mathsf{AD} = \sqrt{\mathsf{AB}^2 + \mathsf{BD}^2} = \sqrt{26^2 + 2^2}$ .

Consider right triangle $\triangle \mathsf{ADG}$ (third diagram.) In this triangle,

Segment $\mathsf{AG}$ is the hypotenuse, while
$\mathsf{AD}$ and $\mathsf{DG}$ are the two legs.

$\mathsf{AD} = \sqrt{26^2 + 2^2}$ . The length of segment $\mathsf{DG}$ is the same as the height of the rectangular prism, $2$ (inches.) Apply the Pythagorean Theorem to right triangle $\triangle \mathsf{ADG}$ to find the length of the hypotenuse $\mathsf{AG}$ :

$\begin{aligned}\mathsf{AG} &= \sqrt{\mathsf{AD}^2 + \mathsf{GD}^2} \\ &= \sqrt{\left(\sqrt{26^2 + 2^2}\right)^2 + 2^2}\\ &= \sqrt{\left(26^2 + 2^2\right) + 2^2} \\&= 6\sqrt{19} \\&\approx 26.153\end{aligned}$ .

Hence, the length of the longest line segment in this prism is $6\sqrt{19} \approx 26.153$ inches.

5 0

3 years ago

En una camioneta se pueden transportar 28.5 kilogramos. ¿ Cuántas camionetas se necesitan para transportar 484.5 Kg?

r-ruslan [8.4K]

Answer:

The number of trucks required is 17.

Step-by-step explanation:

28.5 kilograms can be transported in a van. How many trucks are needed to transport 484.5 Kg?

For the transportation of 28.5 kg, one truck is required.

Total mass = 484.5 kg

The number of trucks required is

n = total mass/ mass of one

$n=\frac{484.5}{28.5}\\\\n = 17$

3 0

3 years ago

Please help me with this I posted the pic

sergeinik [125]

It’s f. my guy...........................

7 0

2 years ago

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Solve the system using elimination.<br><br> 2x + 3y = 17<br> x + 5y = 19

ale4655 [162]

$\left\{\begin{array}{ccc}2x+3y=17\\x+5y=19&|\text{multiply both sides by (-2)}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+3y=17\\-2x-10y=-38\end{array}\right}\qquad\text{add both sides of equations}\\.\qquad\qquad-7y=-21\qquad\text{divide both sides by (-7)}\\.\qquad\qquad \boxed{y=3}\\\\\\\text{Substitute the value of y to the second equation}\\\\x+5(3)=19\\\\x=15=19\qquad\text{subtract 15 from both sides}\\\\\boxed{x=4}\\\\Answer:\ x=4\ and\ y=3.$

5 0

3 years ago

Please help me if you don't mind

RoseWind [281]

Answer:

qp is congruent to hg

Step-by-step explanation:

since the given is AAS it has to be angle angle side, you have the angles, r is congruent to i and q is congruent to h, so you need the next sides to be congruent

4 0

2 years ago

Read 2 more answers