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NikAS [45]
3 years ago
12

Identify and explain the error

Mathematics
1 answer:
Stolb23 [73]3 years ago
3 0
You would add 10 to 50 then divide both sides of the equation by -10 and you would get x=4 as your final answer. I recommend using the app Photomath:)
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Simplify <br> (2x - 5)(x + 3) = 0
kirza4 [7]

Answer:

x = 5/2, -3

or

x = 2.5, -3

or

2 1/2, -3

Step-by-step explanation:

Brainliest Please!!

- Hermionia

3 0
3 years ago
Read 2 more answers
The number line shows two points with coordinates negative 15 and positive 2.
lapo4ka [179]
I'm gonna say A. It makes the most sense to me.
8 0
3 years ago
Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
4 years ago
Which of the following is grater than 0.30 and less than 0.50?
Mars2501 [29]

None of the numbers on the list of choices that you posted
with the question meets those conditions.


6 0
3 years ago
You are renting a surfboard for the day. The surfboard rental fee is $25 with an additional charge of $7 per hour. You have at m
o-na [289]

Initial fee: $25

Per hour fee: $7

Your budget: $60

x = # of hours you can rent the surfboard

$25 + $7x ≤ $60

Subtract $25 from both sides.

$7x ≤ $35

Divide both sides by $7

x ≤ 5

You can rent the surfboard for less than or equal to 5 hours.

6 0
3 years ago
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