Question

Write each sum using summation notation. 1+ 3 + 5 + 7 + ⋯ + 99

Answer 1

Answer:

$\Sigma(2n-1) \left \{ {{n=50} \atop {n=1}} \right. \hspace{5} n\in N$

Step-by-step explanation:

First, we need to find the sequence associated to the summation. As you can see the sum only takes odd numbers into account. Hence the sequence it is defined by:

$2n-1$

Where:

$n\in N$

Now, we only need to find the limits of the summation:

Evaluating n=1

$2(1)-1=2-1=1$

Evaluating n=50

$2(50)-1=100-1=99$

Therefore the summation can be written as:

$\Sigma(2n-1) \left \{ {{n=50} \atop {n=1}} \right.$