Answer:
The answer is 16.
Step-by-step explanation:
Answer:
40%
Step-by-step explanation:
Experimental-theoretical over theoretical.
17/3 most likely it depends on what was needed
If the position at time <em>t</em> is
<em>s(t)</em> = (1 m/s³) <em>t</em> ³
then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is
<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)
<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)
<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)
<em>v</em> (ave) ≈ 12.006 m/s
Answer: 300 percent
Step-by-step explanation:
Where: 15 is the old value and 60 is the new value. In this case we have a positive change (increase) of 300 percent because the new value is greater than the old value.
