Answer:
8x^2 with 40 as the numerator
Step-by-step explanation:
Answer:
3x-8<23 and -4x+26>6
x<31/3 x<5
Step-by-step explanation:
3x-8<23
Add 8 to both sides
3x<31
Then divide 3 to both sides
x<31/3
and -4x+26>6
Minus 26 to both sides
-4x>-20
You divide -4 to both sides
Keep in mind that everytime you divide a negative the inequality will change so > will be <
x<5
Equation= x divided by -9 = -16
solve= 9 x 16 = 144
answer is 144
We cannot solve for a numerical value of p, but rather set the equation equal to p.
w = 4/(p+2)
(Multiply both sides by the denominator)
w(p+2) = 4
(divide both sides by w)
p+2 = 4/w
(Subtract 2 from both sides) (also 2/1)
p = (4-2)/w
p = 2/w
The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
<h3>How to determine the functions?</h3>
A quadratic function is represented as:
y = a(x - h)^2 + k
<u>Question #6</u>
The vertex of the graph is
(h, k) = (-1, 2)
So, we have:
y = a(x + 1)^2 + 2
The graph pass through the f(0) = -2
So, we have:
-2 = a(0 + 1)^2 + 2
Evaluate the like terms
a = -4
Substitute a = -4 in y = a(x + 1)^2 + 2
y = -4(x + 1)^2 + 2
<u>Question #7</u>
The vertex of the graph is
(h, k) = (2, 1)
So, we have:
y = a(x - 2)^2 + 1
The graph pass through (1, 3)
So, we have:
3 = a(1 - 2)^2 + 1
Evaluate the like terms
a = 2
Substitute a = 2 in y = a(x - 2)^2 + 1
y = 2(x - 2)^2 + 1
<u>Question #8</u>
The vertex of the graph is
(h, k) = (1, -2)
So, we have:
y = a(x - 1)^2 - 2
The graph pass through (0, -3)
So, we have:
-3 = a(0 - 1)^2 - 2
Evaluate the like terms
a = -1
Substitute a = -1 in y = a(x - 1)^2 - 2
y = -(x - 1)^2 - 2
Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
Read more about parabola at:
brainly.com/question/1480401
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