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docker41 [41]
3 years ago
7

Can someone help me with this please?

Mathematics
1 answer:
muminat3 years ago
6 0
(2/3)^(1-1) + (2/3)^(2-1) + (2/3)^(3-1) + (2/3)^(4-1)=
(2/3)^0 + (2/3)^1 + (2/3)^2 + (2/3)^3= 
1 + (2/3) + (4/9) + (8/27) = 
(27/27) + (18/27) + (12/27) + (8/27) =
65/27 = 2 11/27
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Answer:

<em>550ft²</em>

Step-by-step explanation:

<em>Since we are not given the dimension of the rectangular prism. Let us assume;</em>

Length of the rectangular base L = 10ft

Width of the rectangular base W = 15ft

height of the prism H = 5ft

Total surface area of the prism = 2(LW + WH + LH)

Substitute the given values

Total surface area of the prism = 2{10*15 + 15*5 + 10*5}

Total surface area of the prism = 2(150+75+50)

Total surface area of the prism = 2(275)

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MrRissso [65]

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Answer:

13

Step-by-step explanation:

Diagonals of a rhombus are perpendicular bisector.

Hence, triangle ABE so formed would be a right triangle right angled at E.

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AB =  \sqrt{AE^2 + BE^2 }  \\  \\  \therefore \: AB =  \sqrt{5^2 + 12^2 }  \\  \\  =  \sqrt{25 + 144}  \\  \\  =  \sqrt{169}  \\  \huge \red { \boxed{ \therefore \: AB= 13}}

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