Number 1 is 6 number two is -8 and number three is -10
Answer:
<em>x² + 2x - 15 = 0 </em>
Step-by-step explanation:
- 5 and 3 are zeros of quadratic function.
(x + 5)(x - 3) = 0
<em>x² + 2x - 15 = 0</em>
Answer:
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A^2-5a = 6
a^2-5a-6 = 0
Discriminant = (-5)^2-4(1)(-6) = 49
Discriminant is positive so there are two solutions
