They are both the same equations, the procedure to obtain x value will be equivalent.
Answer:
5: 1, 2, 4, 11, 22, 44
6: 1, 5, 25, 125
7: 1, 5, 17, 85
8: 1, 3, 13, 39
Answer:
Step-by-step explanation:
a. (11x) + (22x)= 33x
b. (-6x) - (-6x) = 0
c. (-13) + (14x) - (+13t) = -13t + 14x - 13
d. (-4t) + (+4t) - (-6t) = 6t
Answer:
They are taking 12 2 credit courses
The are taking 4 1 credit courses
Step-by-step explanation:
x = 1 credit courses
y = 2 credit courses
The number of courses is 16
x+y = 16
The number of credits is 28 so multiply the course by the number of credits
1x+2y=28
Subtract the first equation from the second equation
x+2y =28
-x-y=-16
-----------------
y = 12
They are taking 12 2 credit courses
We still need to find the 1 credit courses
x+y = 16
x+12= 16
Subtract 12 from each side
x-12-12 = 16-12
x =4
The are taking 4 1 credit courses
