Answer:
2/5
Step-by-step explanation:
5/5 = full job
3/5 = done
full job - done = remaining
5/5 job - 3/5 job
= 2/5 (remaining)
The correct answer is 2.5 cm
Explanation:
In any polygon, the area refers to the total space occupied by the polygon. In the case of triangles, the area can be calculated by multiplying the base and height and then dividing the by 2. This means b x h / 2 = area of a triangle. According to this, the area of the triangle presented is 15
5 cm (base) x 6 cm (height) = 30 cm
30 cm / 2 = 15 cm (total area)
This also means the area of the rectangle is 15 considering both figures have the same area. Additionally, the area in rectangles is calculated by multiplying the length base by the width. This implies in the case presented 6 cm x w cm = 15 cm (total area), and you can determine the value of w by using a simple equation as
6 x w = 15
w = 15 / 6
w = 2.5
Also, you can know this is the correct value because 6 cm (length) x 2.5 (width) = 15 cm which is the correct area
Answer:
undefined
Step-by-step explanation:
To find the slope through 2 points
m = ( y2-y1)/(x2-x1)
= ( -4 - -3)/(3 - 3)
= ( -4+3)/(3-3)
= -1/0
Since it is a number divided by zero, the slope is undefined
Answer:
Step-by-step explanation:
The Fundamental Theorem of Calculus states that:
![\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt \right] = f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%20%5Cint_a%5Ex%20f%28t%29%5C%2C%20dt%20%20%5Cright%5D%20%3D%20f%28x%29)
Where <em>a</em> is some constant.
We can let:
By substitution:
Taking the derivative of both sides results in:
![\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20g%27%28s%29%20%3D%20%5Cfrac%7Bd%7D%7Bds%7D%5Cleft%5B%20%5Cint_6%5Es%20g%28t%29%5C%2C%20dt%5Cright%5D)
Hence, by the Fundamental Theorem:
Ok the ladder and the ground will make a right triangle/right angle. This is because the ground is flat, the wall is straight and only the ladder is leaning/slanted. I hope this helps.
