Hello,
Let's assume a,b,c the 3 sides of the triangle.
a=9
b=10
c=24-a-b=5
We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!
We are given with ;
Take LCM on both sides :
<em>Multiplying</em> both sides by <em>10</em> ;

Can be <em>further written</em> as ;
Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>


Answer:
Step-by-step explanation:
n²+2n+1 = (n+1)(n+1)
n²-8n-9 = (n+1)(n-9)
the least common denominator for these two rational expressions is :
(n+1)(n-9)
Answer:
<h2>X = 0</h2><h2>Y = 1</h2>
First of all, observe that this is a line, since you can rewrite the equation as y−x+1=0 , which follows the pattern of the generic line ax+by+c=0 .
To draw a line you need two of its points, which you can connect.
To find two points, you can plug any value for one variable, and solve for the other.
For example, let's choose
x=0 . The equation becomes
0−1=y , and so y=−1 .
The first point is thus (0,−1).
Then, let's choose
x=1 . The equation becomes 1−1=y , and so y=0 . The first point is thus
(1,0).
Now you only need to draw the points
(0,−1)
Step-by-step explanation:
Hope it is helpful...