Let's say Bailey takes "b" days to paint it.
and Andrew takes "a" days to paint the same house.
now, Andrew is 6 times faster than Bailey, therefore, if Andrew takes "a" days to do it, Bailey takes then "6a" days, or b = 6a.
now, the year they worked together, they finished it in 7 days.
so, after 1 day then, they have only done 1/7 of the whole work.
and Andrew for one day, has done 1/a of the house, whilst Bailey has done 1/b of the house or 1/(6a).

The answer is C to this question
Answer:
the answer is b.11
Step-by-step explanation:
Answer:

Step-by-step explanation:
We are looking for what number times .50 makes the equation true.
So, just do backwards equation:


Thus, meaning that what multiplied by 0.50 is equal to 17?
[tex]0.50 * 34[tex]
[tex]==> 17[tex]