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3 years ago

Solve y=x^2-5 for x

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

7 0

Answer:

x^2 - 5 = y

x^2= y + 5

$x \: = \: \sqrt{y + 5}$

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A marble factory ships marbles using bags of 10, cases of 100, cartons of 1,000, and boxes of 10,000. The factory has an order f

disa [49]

They factory could use 35 cases of 100 and 7 bags of 10.

I hope my answer helps. =)

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3 years ago

Help this is really hard

Agata [3.3K]

(2^8 *3^-5* 6^0)^-2 * ((3^-2)/(2^3))^4 * 2^28

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1*9

5 0

3 years ago

Read 2 more answers

I WILL GIVE BRAINLIEST!!!

hram777 [196]

Answer:

Step-by-step explanation:

6 0

3 years ago

Solve for x,<br> m-3x=2x+p

just olya [345]

<span>m-3x=2x+p
m-x=p (- 2x on both sides)
-x=p-m (- m on both sides)
answer: x=-p+m (divide -1 on both side)

</span>

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3 years ago

What are the coordinates of the turning point for the function f(x) = (x - 1)3 - 3? A. (-1, -3)

Naddik [55]

ANSWER

The turning point is

$(1,-3).$

EXPLANATION

The function given to us is

$f(x) = (x - 1) ^{3} - 3$

At turning point,
$f '(x) = 0$

So we need to differentiate the given function and equate it to zero.

We using the chain rule of differentiation, we obtain,
$f '(x) =3 (x - 1) ^{2}$

We equate this to zero to obtain,

$3 (x - 1) ^{2} = 0$

We divide through by 3.

$(x - 1) ^{2} = 0$

We solve for x to get,

$x - 1 = 0$

$x = 1$

We substitute this x-value in to the function to obtain the corresponding y-value of the turning point.

$f(1) = (1- 1) ^{3} - 3$

$f(1) = 0 - 3$

$f(1) = - 3$

Therefore the turning point is

$(1,-3)$

C is the correct answer.

6 0

3 years ago

Read 2 more answers

Solve y=x^2-5 for x​

Solve y=x^2-5 for x