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Aleks [24]
2 years ago
12

8x8-5x20 12 45 64 -36 -15 -10

Mathematics
2 answers:
Orlov [11]2 years ago
6 0
-36 because 64-100 (separate the terms)
Oduvanchick [21]2 years ago
4 0

The answer is negative 36. -36

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to rent a building for a school dance ava paid $120 plus $2.50 for each student who attended. If she paid a total cost of $325 h
deff fn [24]

Answer:

82 students

Step-by-step explanation:

8 0
3 years ago
A parabola intersects the x-axis at x=3 and x=9 what is the x-coordinate of the parabola's vertex?
KiRa [710]

Here we are given the x intercepts at x=3 and x=9

So let us try to make quadratic equation for this using given information.

We have factors in the form (x-a)(x-b)

where a and b are x intercepts given to us.

So rewriting in factored form:

y=(x-3)(x-9)

Now let us simplify it:

y=x^{2}-12x+27

Let us find the vertex now,

For a quadratic equation of the form:

y=ax^{2}+bx+c

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x=\frac{-b}{2a}

So using this formula for our equation,

x=\frac{-(-12)}{2(1)}

So x = 6

Answer: The x-coordinate of the parabola's vertex is 6.


7 0
3 years ago
Read 2 more answers
Water is flowing into a large spherical tank at a constant rate. Let V (t) be the volume of water in the tank at time t, and h(t
aleksley [76]

Answer:

See solutions for detail.

Step-by-step explanation:

a.  \frac{dV}{dt} is the instantaneous rate of change of volume given with respect to time, t.

The volume's rate of change is written as a function of time.

-\frac{dh}{dt} is the rate of change in the height of water in the tank with respect to time, t.

b.  \frac{dV}{dt}- is the only constant. Water flows into the constant at a constant rate, say 6cm^3 per minute.

c. \frac{dV}{dt} is positive. Volume water in the take  is increasing from time to time.

-The volume at time t=1 is greater than the volume at t=0, hence, it's a positive rate of change.

d. \frac{dh}{dt} is a positive rate. The initial height of water in the tank is zero.

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8 0
3 years ago
Working alone and at a constant rate, Machine A takes 3 hours to create a widget. Machine B, working alone and at a constant rat
PilotLPTM [1.2K]

Answer:

Time required by Machine B to create a widget = 4 hours

Step-by-step explanation:

Time taken by Machine A ( T_{A} ) = 3 hours

Time taken by Machine B ( T_{B} )= x hours

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The time required to both machines by  working together to finish a task is given by the formula = \frac{T_{A} {T_{B} } }{T_{A} + T_{B} }

Put the values in above formula we get

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