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3 years ago

Need help please!!!!!

Mathematics

1 answer:

Yanka [14]3 years ago

6 0

Answer:

Side 1 = 8, side 2=6, side 3=3 1/3 or 10/3

Step-by-step explanation:

We can set up a proportion comparing the sides of the original triangle to the new triangle.

The original triangle has sides 12, 9, and 5. The new triangle has sides 8, e, and f (use whatever letters you like, it doesn't matter, but for me, e is the side with the middle length and f is the side with the shortest length.

We can write 3 ratios, with the length of the new triangle over the length of the old triangle.

8/12 e/9 f/5

To figure out e and f, put each ratio equal to 8/12.

8 = e Then multiply both sides of the equation by 9 and get 72 = e, 6=e.

12 9 12

8 = f Then multiply both sides of the equation by 9 and get 40 = f, 10=f.

12 5 12 3

10/3 can be rewritten as 3 1/3.

You might be interested in

a library has an average of 510 visitors on Sundays and 240 visitors on other days. The average number of visitors per day in a

serious [3.7K]

Answer:

285

Step-by-step explanation:

personally this is how i would do this question but there are other ways.

i would start off by seeing how many sundays there are in the month (which is 5) then the number of other days which is 25. i'd then multiply 5 by 510 which is 2550. add that to 240 times 25 (which is 6000) and all of that together is 8550. divide that by the number of the days in the month (30) and then you'll get the daily avergae for the month

hope this helped:)

6 0

3 years ago

Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|

Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0

3 years ago

What is the domain of the graph?

maksim [4K]

Domain:
-4 ≤ x ≤ 3
or in different form:
x ∈ [-4; 3]

4 0

3 years ago

Variable a is 4 more than variable b. Variable a is also 1 less than b. Which of the following pairs of equations best models th

Elis [28]

B=a+4 that is what the answer will be.

4 0

3 years ago

a craftsman drill is on sale for $99.99. If the sales tax rate is 7%, how much will molly have to pay for the drill?

Nadya [2.5K]

99.99 x (7%/100)= 6.9993
99.99+6.9993= 106.9893 (round up)
ANWSER- $106.99
Hope this helped.

8 0

3 years ago