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3 years ago

Solve for X if X +127 equals 185

Mathematics

2 answers:

hoa [83]3 years ago

4 0

Answer:X=58

Step-by-step explanation:

AleksandrR [38]3 years ago

4 0

Answer:

Step-by-step explanation:

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In a Gallup poll of randomly selected adults, 66% said that they worry about identity theft. For a group of 1013 adults, the mea

Kazeer [188]

Answer:

$Mean = 344$

Step-by-step explanation:

Given

$Population = 1013$

Let p represents the proportion of those who worry about identity theft;

$p = 66\%$

Required

Mean of those who do not worry about identity theft

First, the proportion of those who do not worry, has to be calculated;

Represent this with q

In probability;

$p + q = 1$

Make q the subject of formula

$q = 1 - p$

Substitute $p = 66\%$

$q = 1 - 66\%$

Convert percentage to fraction

$q = 1 - 0.66$

$q = 0.34$

Now, the mean can be calculated using:

$Mean = nq$

Where n represents the population

$Mean = 1013 * 0.34$

$Mean = 344.42$

$Mean = 344$ (Approximated)

3 0

3 years ago

PLEASEE help

ASHA 777 [7]

Answer:

there are 196.85 inches in 5 meters so rounding o the nearest inch would be

197 or 200

Step-by-step explanation:

5 0

3 years ago

What is the value of 60tens

Aleonysh [2.5K]

Answer:

if your saying there are sixty different tens, then your answer is 600.

Step-by-step explanation:

10 * 60 = 600

6 0

3 years ago

Consider the probability that at most 85 out of 136 DVDs will work correctly. Assume the probability that a given DVD will work

Hoochie [10]

Answer:

Since both $np \geq 10$ and $n(1-p) \geq 10$ , the necessary conditions are satisfied.

0.9945 = 99.45% probability that at most 85 out of 136 DVDs will work correctly.

Step-by-step explanation:

Test if the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.

It is needed that:

$np \geq 10$ and $n(1-p) \geq 10$

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .