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Naddik [55]
3 years ago
11

Solve for X if X +127 equals 185

Mathematics
2 answers:
hoa [83]3 years ago
4 0

Answer:X=58

Step-by-step explanation:

AleksandrR [38]3 years ago
4 0

Answer:

58

Step-by-step explanation:

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Tell whether the triangle with the given side lengths is a right triangle.<br> 10in., 24in., 26in.
ra1l [238]
Answer- Yes it is a right triangle.
You can use the Pythagorean Theorem.
( a^2 + b^ = c^2 ) and replace a with 10, b with 24, and c with 26 and the equation will be balanced on both sides.

(10^2 + 24^2 = 26^2)
(100 + 576 = 676 )
4 0
3 years ago
Molly earns a rebate each month on her movie tickets and books. She earns $0.25 for each movie ticket and $2 for each book. Last
Sliva [168]

The algebraic equation is 4(0.25)+2x=17

STEP 1: Simplify both sides of the equation

1+2x=17  or  2x+1

STEP 2: Subtract both sides

2x = 16

STEP 3: Divide both sides by 2

2x/2 = 16/2

x = 8

Molly purchased 8 books last month

7 0
3 years ago
Two customers went to a post office to buy postcards and large envelopes. Each postcard
astraxan [27]

The right answer is Option A.

Step-by-step explanation:

Let,

x be the postcards

y be the large envelops

According to given statement;

14x+5y=12   Eqn 1

10x+15y=24.80   Eqn 2

Multiplying Eqn 1 by 3;

3(14x+5y=12)\\42x+15y=36\ \ \ Eqn \ 3

Subtracting Eqn 2 from Eqn 3;

(42x+15y)-(10x+15y)=36-24.80\\42x+15y-10x-15y=11.20\\32x=11.20\\

Dividing both sides by 32

\frac{32x}{32}=\frac{11.20}{32}\\x=0.35

Putting x=0.35 in Eqn 1;

14(0.35)+5y=12\\4.90+5y=12\\5y=12-4.90\\5y=7.10

Dividing both sides by 5

\frac{5y}{5}=\frac{7.10}{5}\\y=1.42

Therefore, one large envelope costs $1.42

The right answer is Option A.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/9738996
  • brainly.com/question/10015690

#LearnwithBrainly

4 0
3 years ago
Find two number nearest to 8888888 which are exactly divisible by 2915​
Marysya12 [62]

Step-by-step explanation:

Given problem is to find nearest number,

= 8888888/2915

quotient = 3049

remainder= 1053

Now, 2915-1053 = 1862

8888888+1862 = 8890750

8888888-1053 = 8887835

Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750

3 0
2 years ago
Hello there I need help.
andriy [413]

Answer:

A. 40

Step-by-step explanation:

Q1 - 40

Q2 - 65

Q3 - 80

And 90 is max

So 40 is the correct answer.

5 0
3 years ago
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