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3 years ago

Solve for X if X +127 equals 185

Mathematics

2 answers:

hoa [83]3 years ago

4 0

Answer:X=58

Step-by-step explanation:

AleksandrR [38]3 years ago

4 0

Answer:

Step-by-step explanation:

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Find the sum (2x−6)+4(x−3) =

xeze [42]

Answer: x=-2

Step-by-step explanation: First we can multiply 4 times anything in the parantheses to get rid of it.

(2x-6)+4(x-3)

(2x-6)+4x-12

Then we combine like terms.

(2x-6)+4x-12

6x-6-12

6x-18

Finally we divide both sides 6.

6x-18

6x/6-18/6

x=-2

The final answer is x=-2

Hope this helps!

Btw this is a backup account

7 0

3 years ago

Read 2 more answers

Your hourly salary increased from $14 to $29. What is the percent increase in your<br> salary?

V125BC [204]

Answer:

107%

Step-by-step explanation:

$14 to $29

Original number/start = $14

End number = $29

Increase = $29 - $14 = $15

% increase = Increase ÷ Original Number × 100

Substitute in known values

% increase = 15 ÷ 14 × 100

Divide

% increase = 1.07 × 100

Multiply

% increase = 107%

The percentage increase is 107%

Hope this helps :)

4 0

4 years ago

Read 2 more answers

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

I NEED HELP REALLY QUICK (IN DBA)<br> find the dot product of the uv given: u v=

nataly862011 [7]

9514 1404 393

Answer:

Step-by-step explanation:

u =<2,5> v=<7,1>

The dot product is the scalar sum of products of corresponding components:

u·v = 2·7 + 5·1 = 14 +5 = 19

The dot product is 19.

7 0

3 years ago

What is the difference in speed between two cars when one traveled 175 km in 4 hours and the other traveled the same distance in

vovangra [49]

<h3>Given :</h3>

Distance = 175
Time 1 = 4 hours

$\\ \\$

Different between two speeds when distance is same.

$\\ \\$

<h3>Solution:</h3>

In first part we will find speed 1 in which time is 4 hours

we know:-

$\bigstar \boxed{ \rm speed = \frac{distance}{time} }$

So:-

$\dashrightarrow\sf speed_1 = \dfrac{distance}{time_1}$

$\\ \\$

$\dashrightarrow\sf speed_1 = \dfrac{175}{4}$

$\\ \\$

$\dashrightarrow\bf speed_1 = 43.75 \: km {h}^{ - 1}$

In first part we will find speed 2 in which time is 3 hours

Again:

$\bigstar \boxed{ \rm speed = \frac{distance}{time} }$

$\\ \\$

$\dashrightarrow\sf speed_2 = \dfrac{distance}{time_2}$

$\\ \\$

$\dashrightarrow\sf speed_2 = \dfrac{175}{3}$

$\\ \\$

$\dashrightarrow\bf speed_2 = 58.33kmh^{-1}$

$\\ \\$

In this part we will find different between speed 1 and speed 2

$\bigstar \boxed{\rm Difference = speed_2 - speed_1}$

$\\ \\$

So :

$\dashrightarrow\sf Difference = speed_2 - speed_1 \\$

$\\ \\$

$\dashrightarrow\sf Difference =58.33 - 43.75\\$

$\\ \\$

$\dashrightarrow\bf Difference =14.58kmh^{-1}\\$

$\\ \\$

$\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}$

4 0

3 years ago

Solve for X if X +127 equals 185￼

Solve for X if X +127 equals 185