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3 years ago

If a equals 4b - 15 what is b

Mathematics

1 answer:

nlexa [21]3 years ago

7 0

Answer:

b = a + 3.75

Step-by-step explanation:

a = 4b - 15

You are solving for b. Isolate the b. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, add 15 to both sides

a (+15) = 4b - 15 (+15)

a + 15 = 4b

Next, divide 4 from both sides. Remember to divide from all terms.

(4a + 15)/4 = (4b)/4

b = (4a)/4 + (15)/4

b = a + 15/4

b = a + 3.75 is your answer

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Write the explicit rule for the nth term. Then find a71. {O, -8, -16, -24 ...}

yulyashka [42]

Answer:

Step-by-step explanation:

{0, -8, -16, -24,...} here you add -8 each time so the rule is

$a_{1} = 0, a_{n} = a_{n-1} -8$

the 71 term is

$a_{71} = 0 + (71 - 1) * (-8) = 70 * (-8) = -560$

3 0

3 years ago

A newspaper provided a "snapshot" illustrating poll results from 1910 professionals who interview job applicants. The illustrat

Vedmedyk [2.9K]

Answer:

The correct option is A) Confidence level

Step-by-step explanation:

Consider the provided information.

From the provided information we get the sample size is 1910 professionals

The illustration showed that 26% of them said the biggest interview turnoff is that the applicant did not make an effort to learn about the job or the company. That's mean the point estimate is 26%

The margin of error was given as plus or minus 3±3 percentage points. The margin of error is the confidence interval which is plus or minus 3±3.

Now consider the provided option:

The correct option is A) Confidence level

Because from the above information we know the point estimate is 26% Sample size is 1910 and the confidence interval is 3±3.

5 0

2 years ago

Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I

dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06$