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Thepotemich [5.8K]
3 years ago
8

Extra points not in words

Mathematics
1 answer:
Mashcka [7]3 years ago
6 0
Step^1: 6 - 1 - 2(n) + 5 \\ Step^2: 2(n) = 0 \\ Step ^3: \frac{2n}{0} = 0 ; \\ Step^4 \frac{0}{0} = 0 \\ Step^5:Answer : n = 0 \\ Step^6: Number Of Solutions: 1Solution
good\\luck\\on\\your \\ assignment
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James goes to Walmart and spends, d, dollars. He has a coupon for 25% off. What is James total after the coupon is applied?
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Answer:

c

Step-by-step explanation:

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For the expression y + 6 − 3, determine the coefficient for the variable term.
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The coefficient is the number in front of the variable. If there isn't a number, it is understood to be a 1
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Describe different ways that you can show a story problem
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3 0
3 years ago
A firework is launched at the rate of 10 feet per second from a point on the ground 50 feet from an observer. to 2 decimal place
Kazeer [188]

The rate of change of the angle of elevation when the firework is 40 feet above the ground is 0.12 radians/second.

First we will draw a right angle triangle ΔABC, where ∠B = 90°

Lets, assume the height(AB) = h and base(BC)= x

If the angle of elevation, ∠ACB = α, then

tan(α) = \frac{AB}{BC} = \frac{h}{x}

Taking inverse trigonometric function, α = tan⁻¹ (\frac{h}{x}) .............(1)

As we need to find the rate of change of the angle of elevation, so we will differentiate both sides of equation (1) with respect to time (t) :

\frac{d\alpha}{dt}=[\frac{1}{1+ \frac{h^2}{x^2}}]*(\frac{1}{x})\frac{dh}{dt}

Here, the firework is launched from point B at the rate of 10 feet/second and when it is 40 feet above the ground it reaches point A,

that means h = 40 feet and \frac{dh}{dt} = 10 feet/second.

C is the observer's position which is 50 feet away from the point B, so x = 50 feet.

\frac{d\alpha}{dt}= [\frac{1}{1+ \frac{40^2}{50^2}}] *\frac{1}{50} *10\\ \\ \frac{d\alpha}{dt} = [\frac{1}{1+\frac{16}{25}}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt} = [\frac{25}{41}] *\frac{1}{5}\\   \\ \frac{d\alpha}{dt}= \frac{5}{41} =0.1219512

= 0.12 (Rounding up to two decimal places)

So, the rate of change of the angle of elevation is 0.12 radians/second.

5 0
3 years ago
What is the height of this isosceles triangle?
erastova [34]

Answer:

height ≈ 11.9 units

Step-by-step explanation:

Construct a perpendicular bisector from the vertex to the base, thus splitting the triangle into 2 right triangles.

Using the sine ratio in one of these right triangles, then

sin48° = \frac{opposite}{hypotenuse} ( the opposite is the height h )

sin48° = \frac{h}{16} ( multiply both sides by 16 )

16 × sin48° = h , thus

h ≈ 11.9 ( to the nearest tenth )

5 0
3 years ago
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