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3 years ago

The question is on the picture :)

Mathematics

1 answer:

VashaNatasha [74]3 years ago

7 0

Answer:

2.5

Step-by-step explanation:

y=kx, k is constant of prop

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Mateo and Tyrone collect baseball cards. Mateo has 27 pages in his binder with 9 cards on each page. If the boys have a total of

Rudiy27

The answer is B: (27x9)+c=748

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2 years ago

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A circle has a diameter of 26 units. What is the area of the circle to the nearest hundredth of a square unit? Use 3.14 for pi.

Sholpan [36]

A=pi(r)^2

We have the diameter. To get the radius divide it by 2.

The radius now is equal = 13.
Pi=3.14

Distribute it to the equation... A=3.14(13)^2

The area is equal = 530.66

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3 years ago

A kid has 3 balls he gives his friends 2 how many do they have left

Olin [163]

Answer:

1 left

Step-by-step explanation:

3 - 2 =1 You subtract then u get your answer

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3 years ago

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What does a 23/100 reduced to?

natima [27]

Answer:

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Step-by-step explanation:

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3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago