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victus00 [196]
3 years ago
11

The question is on the picture :)

Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0

Answer:

2.5

Step-by-step explanation:

y=kx, k is constant of prop

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Which triangles are similar?
lara31 [8.8K]
I’m pretty sure it would be a and b
3 0
3 years ago
Consider the one-sided confidence interval expressions for the mean of a normal population. Round your answers to 2 decimal plac
ser-zykov [4K]

Answer: a) 0.84  b) 0.67  c) 1.28

Step-by-step explanation:

Using the standard normal distribution table for z-value , we have

(a) The value of z_{\alpha} would result in a 80% one-sided confidence interval : z_{(1-0.80)}=z_{0.20}=0.8416\approx0.84

(b) The value of z_{\alpha} would result in a 85% one-sided confidence interval : z_{(1-0.85)}=z_{0.25}=0.6744897\approx0.67

(c) The value of z_{\alpha} would result in a 90% one-sided confidence interval : z_{(1-0.90)}=z_{0.10}=1.2815515\approx1.28

6 0
3 years ago
The first three steps in determining the solution set of the system of equations algebraically are shown in the table. y = −x2 +
lianna [129]
You have a system of equations \left \{ {{y = -x^2+2x-9} \atop {y =-6x+6}} \right..

1. Substitude right side of second equation into the left side of the first equation: -6x+6=-x^2+2x-9.

2. Solve this equation:
 x^2-2x+9-6x+6=0, \\ x^2-8x+15=0, \\ D=(-8)^2-4\cdot 1\cdot 15=64-60=4,  \\ \sqrt{D}=2,  \\ x_{1,2}=\dfrac{8\pm 2}{2  } =3,5.

3. Find y:
for x_1=3, y_1=-6\cdot 3+6=-18+6=-12,
for x_2=5, y_2=-6\cdot 5+6=-30+6=-24.

4. The solutions of the system are: (3,-12) and (5,-24).
Answer: Correct choice is A.


7 0
3 years ago
Read 2 more answers
За – 6а + 2 = 8а + 20 – 5а
Luda [366]

Answer:

a = -3

Step-by-step explanation:

3a - 6a + 2 = 8a + 20 - 5a

Combine Like Terms

-3a + 2 = 3a + 20

       -2            -2

-------------------------------------

-3a = 3a + 18

-3a  -3a

-------------------------------------

-6a = 18

----   ----

-6     -6

a  =  -3

4 0
2 years ago
Y = 2/3 x -3 y = -3/2 x +2 what statement about the lines are true
Hoochie [10]

Answer:

The product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

Thus, the lines are perpendicular.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the lines

y = 2/3 x -3       --- Line 1

y = -3/2x +2      --- Line 2

<u>The slope of line 1</u>

y = 2/3 x -3       --- Line 1

By comparing with the slope-intercept form of the line equation

The slope of line 1 is: m₁ = 2/3

<u>The slope of line 2</u>

y = -3/2x +2      --- Line 2

By comparing with the slope-intercept y = mx+b form of the line equation

The slope of line 2 is: m₂ = -3/2

We know that when two lines are perpendicular, the product of their slopes is -1.

Let us check the product of two slopes m₁ and m₂

m₁ × m₂ = (2/3)(-3/2 )

m₁ × m₂ = -1

Thus, the product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

Thus, the lines are perpendicular.

7 0
2 years ago
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