Answer:
6d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 12cd^4 + 8
Step-by-step explanation:
We need to subtract the given polynomial from the sum:-
8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9 - (2d^5 - c^3d^4 + 8cd^4 +1 )
We need to distribute the negative over the parentheses:-
= 8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9 - 2d^5 + c^3d^4 - 8cd^4 -1
Bringing like terms together:
= 8d^5 - 2d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 4cd^4 - 8cd^4 + 9
- 1
Simplifying like terms
= 6d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 12cd^4 + 8
Answer:
Step-by-step explanation:
Through -3 , -2 slope = -2/3
y1 = -2 & x1 = -3 and m = -2/3
y - y1 = m(x - x1)
y - (-2) = -2/3(x - (-3))
y + 2 = -2/3(x + 3)
Multiply each term by 3
3y + 6 = -2(x + 3)
3y + 6 = -2x - 6
3y = -2x - 6 - 6
3y = -2x - 12
There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.
The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758
We can make several two 3-digit numbers from these blocks. An example is listed below:
Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:
1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434
The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.
This way changing the number of blocks in each place value, different 3 digit numbers can be generated.
Answer:
c
Step-by-step explanation:
the answer is c
alernate angles are angles that take the shape of z
Answer:
B :point 2 and point 3
Step-by-step explanation:
The only interior angles are 6, 2, 3, and 7
The angles equal to each other are 6 and 7 or 2 and 3
6 and 7 is not an option so 2 and 3 are the correct answer.
