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blondinia [14]
3 years ago
7

For two positive real numbers a and b, which may be equal, determine the smallest possible value of a/b + b/a​

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0
Well what i got was 9/2
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Find the value of 5x and 3x+60
Lerok [7]

Answer:0 and -20

Step-by-step explanation:

5x=0;

x=0/5.

3x+60=0;

3x= -60;

x= -60/3;

x= -20

5 0
3 years ago
A rectangle has an area of 20 ft.² in a similar rectangle has an area of 180 ft.² what is the ratio of areas of the similar
vovikov84 [41]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{cccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------\\\\

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s^2}{s^2}=\cfrac{20}{180}\implies \left( \cfrac{s}{s} \right)^2=\cfrac{20}{180}\implies \cfrac{s}{s}=\sqrt{\cfrac{20}{180}}
\\\\\\
\cfrac{s}{s}=\cfrac{\sqrt{20}}{\sqrt{180}}\implies \cfrac{s}{s}=\cfrac{2\sqrt{5}}{6\sqrt{5}}\implies \cfrac{s}{s}=\cfrac{2}{6}\implies \cfrac{s}{s}=\cfrac{1}{3}
6 0
3 years ago
A function, f(x) = 4x + 5, has a domain 0 < x < 50. What is its range?
Roman55 [17]

Answer:

f(x) = 4x+5 ; 0 ≤ x ≤ 50

 

The range is the possible output values of f(x)

 

4(0) + 5 = 5       smallest output value in range

4(50) + 5 = 55    largest output value in range

 

The outputs are between 5 and 55 including the endpoints so

the range is [5, 55]

7 0
3 years ago
Read 2 more answers
Simplify <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7Bx-6%7D%20%2B%20%20%5Cfrac%7B3%7D%7Bx%2B5%7D%20" id="TexFormula1"
Svetradugi [14.3K]
Combine the fractions by finding a common denominator.<span><span><span><span>     7x</span>+2
</span><span><span>--------------
(<span>x+5</span>)</span><span>(<span>x<span>−6</span></span>)</span></span></span></span>
7 0
3 years ago
Read 2 more answers
OLLEGE
Sophie [7]

<u>Part 1</u>

<u />(f\circ g)(x)=f(\sqrt{x})=4\sqrt{x}+1

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus, the domain is \boxed{[0, \infty)}

<u>Part 2</u>

<u />(g \circ f)(x)=g(4x+1)=\sqrt{4x+1}

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,

4x+1 \geq 0\\\\4x \geq -1\\\\x \geq -\frac{1}{4}

Thus, the domain in interval notation is \boxed{\left[-\frac{1}{4}, \infty)}

8 0
2 years ago
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