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kirill115 [55]
3 years ago
7

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s a slant height of 2 cm and a radius of 1 cm. The lateral area of the cone is π cm2. To wrap paper around the entire lateral surface of the cylinder, π cm2 of paper is needed. The surface area, including the bottom base of the crayon, is π cm2.
Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0

Answer:

Part 1) The  lateral area of the cone is LA=2\pi\ cm^{2}

Part 2) The lateral surface area of the cylinder is LA=36\pi\ cm^{2}

Part 3) The surface area of the crayon is SA=41.50\pi\ cm^{2}

Step-by-step explanation:

Part 1) Find the  lateral area of the cone  

The lateral area of the cone is equal to

LA=\pi rl

we have

r=1\ cm

l=2\ cm

substitute

LA=\pi (1)(2)

LA=2\pi\ cm^{2}

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

LA=2\pi rh

we have

r=1.5\ cm

h=12\ cm

substitute

LA=2\pi (1.5)(12)

LA=36\pi\ cm^{2}

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

<em>Find the area of the bottom base of the crayon</em>

A=\pi[r2^{2}-r1^{2}]

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

A=\pi[1.5^{2}-1^{2}]

A=1.25\pi\ cm^{2}

<em>Find the area of the top base of the cylinder</em>

A=\pi(1.5)^{2}=2.25\pi\ cm^{2}

<em>Find the surface area</em>

SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}

N76 [4]3 years ago
5 0

Answer:

2

36

41.5

Step-by-step explanation:

just got it all right even though I guessed soooo, yay

Step-by-step explanation:

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