<span> <span><span> <span> Part a </span> <span> Segment RS
Hint: What type of segment is RS? </span> <span> 5 cm </span> <span>
RS is the Radius of circle R the diameter of circle P is 10 cm and circle R and P are congruent and a radius is half of ten so 10 / 2 = 5 cm
<span> <span><span> <span> Part c </span> <span> Arc SV
Hint: Read the green Arc Measures box on pg. 231. </span> <span> 35 * </span> <span> Angle SRV = 35 *
Arc SV = 35 *
Because the degree measure of a minor arc is the measure of it’s central angle
<span> <span><span> <span> Part d </span> <span> Area of Circle R Leave your answer in terms of π
Hint: See the example problem on pg. 192.
</span> <span> 25π cm </span> <span> Π r2= π 52
52 = 25 π
25 π cm
</span> </span> </span></span> </span> </span> </span></span> </span> </span> </span></span>
Answer:
-6-(-2) is equivalent to
-6 +2
and 2-6
a) and b) are correct options
Answer: the area of the shaded region is 21.5 cm²
Step-by-step explanation:
The formula for determining the area of a circle is expressed as
Area = πr²
Where
r represents the radius of the circle.
π is a constant whose value is 3.14
From the information given,
Diameter of circle = 10 cm
Radius = diameter/2 = 10/2 = 5 cm
Area of circle = 3.14 × 5² = 78.5 cm²
The length of each side of the square is 10 cm. The area of the square would be
10² = 100 cm²
Therefore, the area of the shaded region would be
100 - 78.5 = 21.5 cm²
Answer:
43.8°
Step-by-step explanation:
Applying,
Cosine rule,
From the diagram attached,
x² = y²+z²-2yxcos∅.................... Equation 1
where ∅ = ∠YXZ
Given: x = 8.7 m, y = 10.4 m, z = 12.4 m
Substitute these values into equation 1
8.7² = 10.4²+12.4²-[2×10.4×12.4cos∅]
75.69 = (108.16+153.76)-(257.92cos∅)
75.69 = 261.92-257.92cos∅
collect like terms
257.92cos∅ = 261.92-75.69
257.92cos∅ = 186.23
Divide both sides by the coefficient of cos∅
cos∅ = 186.23/257.92
cos∅ = 0.722
Find the cos⁻¹ of both side.
∅ = cos⁻¹(0.7220)
∅ = 43.78°
∅ = 43.8°
Answer:
domain=0
range=2
Step-by-step explanation:
this might be helpful..
