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IRISSAK [1]
3 years ago
8

Find the x-intercepts for the parabola defined

Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

<h2>Explanation:</h2>

In this exercise we have the following equation of a parabola:

y=2x^2-12x+10

So our goal is to find the x-intercepts. We can find this setting y=0, so:

2x^2-12x+10=0

Taking 2 as common factor:

2(x^2-6x+5)=0

Hence this is a Non-perfect Square Trinomial. To factor out this, let's choose two numbers such that:

  • The sum is -6
  • The product is 5

Those two numbers are:

  • -1 and -5

Because:

  • Sum: -6
  • Product: 5

So this equation can be written as:

x^2 + (a + b)x + ab=(x + a)(x + b) \\ \\ a=-1 \\ b=-5 \\ \\  x^2-14x+24=(x-(-1))(x-(-5))=0 \\ \\ (x+1)(x+5)=0 \\ \\ So \ the \ solutions \ are: \\ \\ \boxed{x=-1 \ and \ x=-5}

<h2>Learn more:</h2>

Solutions to quadratic equation: brainly.com/question/13742278#

#LearnWithBrainly

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