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Anon25 [30]
3 years ago
8

Taylor is comparing the prices of two mattress cleaning companies. Company A charges $30 per mattress and an additional $15 as s

ervice charges. Company B charges $28 per mattress and an additional $21 as service charges.
Part A: write equations to represent company A’s and Company B’s total mattress cleaning charges for a certain number of mattresses. Define the variable used in the equations.

Part B: which company would charge less for cleaning 6 mattresses? Justify your answer.

Part C: How much money is saved by using the services of Company B instead of Company A to clean 3 mattresses?
Mathematics
1 answer:
Oduvanchick [21]3 years ago
3 0

part A:

company a

30m+15

m= matress

company b

28m+21

m=matresses sold

part B:

company a

30(6)+15

195$

company b

28(6)+21

189$

company B charges less

part C:

company a

30(3)+15

105$

company b

28(3)+21

105$

there is no change at all so you do not save anything.


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Answer:

x = 11, lucky you, this stuff is easy

Step-by-step explanation:

110 - 11 = 99

9 x 11 = 99

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ANEK [815]
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8 0
3 years ago
Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.
lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is <u>tested if the mean lifetime is not greater than 220,000 miles</u>, that is:

H_0: \mu \leq 220000

At the alternative hypothesis, it is <u>tested if the mean lifetime is greater than 220,000 miles</u>, that is:

H_1: \mu > 220000.

We have the <u>standard deviation for the sample</u>, thus, the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem:

\overline{x} = 226450, \mu = 220000, s = 11500, n = 23

Then, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}

t = 2.69

We have a right-tailed test(test if the mean is greater than a value), with <u>t = 2.69</u> and 23 - 1 = <u>22 df.</u>

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0
2 years ago
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tekilochka [14]
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Notice how the negative exponent becomes positive as you flip it.

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I separated the constant (5) from the variable (n) to show you how the powers are evaluated.

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1/(125)(n^12)

= 1/125n^12
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3 years ago
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