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nikitadnepr [17]

2 years ago

10

1 - 2 + 5 - 2 + 5 x 2

2 answers:

tino4ka555 [31]2 years ago

7 0

Answer: 12

Step-by-step explanation:

Following PEMDAS, I’ll solve the multiplication first and then add or subtract the values from left to right.

1-2+5-2+5x2

1-2+5-2+10

-1+5-2+10

4-2+10

2+10

12

CaHeK987 [17]2 years ago

3 0

Answer:

12

Step-by-step explanation:

You need to use the order of operations, PEMDAS. It stands for Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

First, multiplication on 5x2 so now it is 1-2+5-2+10.

Next, is addition and subtraction. When it says left to right you are starting with the part of the equation closest to the left, so 1-2=-1. Then add five to get 4. Subtract 2 to get 2. Finally, add 10 to get 12.

Hope you get an A! <3

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wariber [46]

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3 years ago

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What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

4 years ago

Simplify the expression 14 + 5(x+3)-7

Alenkasestr [34]

14 + 5(x+3)-7
14 + 5x +15 -7
5x + 22

8 0

3 years ago

Need brief explanation about why false is correct

anyanavicka [17]

<u>We are given the equation:</u>

(a + b)! = a! + b!

<u>Testing the given equation</u>

In order to test it, we will let: a = 2 and b = 3

So, we can rewrite the equation as:

(2+3)! = 2! + 3!

5! = 2! + 3!

<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>

120 = 2 + 6

We can see that LHS ≠ RHS,

So, we can say that the given equation is incorrect

6 0

3 years ago