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madreJ [45]
3 years ago
11

A bird flies at an elevation of 10 feet. Which is closer to sea level than the bird?

Mathematics
2 answers:
morpeh [17]3 years ago
7 0

Answer:

B. A boy swimming at an elevation of –3 feet.

Step-by-step explanation:

We have been given that a bird flies at an elevation of 10 feet. We are asked to choose the elevation that is closer to sea level than the bird.

Let us find absolute value of each elevation.

A. A fish swimming at an elevation of –18 feet.

|-18|=18

The fish is 18 feet away from sea level.

B. A boy swimming at an elevation of –3 feet.

|-3|=3

The boy is 3 feet away from sea level.

C. A kite flying at an elevation of 30 feet.

|30|=30

The kite is 30 feet away from sea level.

D. A bird sitting in a tree at an elevation of 12 feet

|12|=12

The bird is 12 feet away from sea level.

Since the distance between the boy swimming and sea level is less than other distances, therefore, the boy is closer to sea level than the bird.

Taya2010 [7]3 years ago
6 0

A boy swimming at an elevation of 3 feet below sea level. This is the answer because the boy is only 3 feet away from sea level while the bird is 10 feet away form sea level.

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Answer:

7

Step-by-step explanation:

1/7+1/3= 3/21+7/21= 10/21= 0.476190

the 6 digits after the decimal point get repeated

6*3= 18- three full cycles and the second digit after 3 cycles = 7 so the 20th digit is 7

5 0
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What is the standard form of the linear function that passes
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• all variables on the left-hand-side, sorted

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\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2(y-1)=2\left( \cfrac{3}{2}(x-4) \right)}\implies 2y-2 = 3(x-4)\implies 2y-2=3x-12 \\\\\\ -3x+2y-2=-12\implies -3x+2y=-10\implies \stackrel{\times -1\textit{ to both sides}}{3x-2y=10}

7 0
3 years ago
A transformation T : (x, y) → (x + 3, y + 1). Find the preimage of the point (4, 3) under the given transformation. (7, 4) (1, 2
motikmotik

Answer:

(1, 2)

Step-by-step explanation:

Remember that the final shape and position of a figure after a transformation is called the image, and the original shape and position of the figure is the pre-image.

In our case, our figure is just a point. We know that after the transformation T : (x, y) → (x + 3, y + 1), our image has coordinates (4, 3).

The transformation rule T : (x, y) → (x + 3, y + 1) means that we add 3 to the x-coordinate and add 1 to the y-coordinate of our pre-image. Now to find the pre-image of our point, we just need to reverse those operations; in other words, we will subtract 3 from the x-coordinate and subtract 1 from the y-coordinate.

So, our rule to find the pre-image of the point (4, 3) is:

T : (x, y) → (x - 3, y - 1)

We know that the x-coordinate of our image is 4 and its y-coordinate is 3.

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                (1, 2)

We can conclude that our pre-image is the point (1, 2).

6 0
3 years ago
1.5 x 32
Bingel [31]
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  </span>
5 0
3 years ago
What figure has properties of all sides congruent and all right angles?
andre [41]
A. Rectangle


Here bestie
7 0
3 years ago
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