-8y^10 / 2y^5 write using positive exponents

Mathematics

1 answer:

Rashid [163]2 years ago

3 0

Answer:

Step-by-step explanation:

$\dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\dfrac{-8y^{10}}{2y^{5}}=\dfrac{-4y^{10}}{y^{5}}=-4*y^{10-5}= -4y^{5}$

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Answer:

$f(x)=x^{3}-3x^{2} +4x-2$

Step-by-step explanation:

we know that

The <u><em>conjugate root theorem</em></u> states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial

In this problem we have that

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