Answer:
The equation of this line would be y = 11x - 48
Step-by-step explanation:
To get this equation, we first have to find the slope. We do that with the slope eqaution.
m(slope) = (y2 - y1)/(x2 - x1)
m = (-4 - 7)/(4 - 5)
m = -11/-1
m = 11
Now we can use this slope and either point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - 7 = 11(x - 5)
y - 7 = 11x - 55
y = 11x - 48
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:
10 n equals 6
Step-by-step explanation:
Why? Because that has nothing to do with the problem and no solution for 3/5.
is equal to 2x, since it is the derivative of
.
Answer:
Step-by-step explanation:
If the questions is "What's x" then the answers is...
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
use CAH
Cos(x) = 46/60
x = arcCos(46/60)
x = 39.9445 °
