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irinina [24]
3 years ago
5

Help I’m so close and I really wanna sleep ;-;

Mathematics
2 answers:
Marianna [84]3 years ago
5 0

Answer:

8

Step-by-step explanation:

Preety Sure is 8

ELEN [110]3 years ago
4 0

Answer:

8

Step-by-step explanation:

Since it starts from 6, count by +1 till you get at the blue dot

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PLEASE HELP ASAP!!!!!!!!!
Butoxors [25]

Answer:

it’s the last one

8 0
3 years ago
I SUCK CAN SOMEONE PLZ DO THIS EVEN WRITING IT OUT FOR ME!?!??
Ksju [112]
Jason is buying 2 hats and 3 scarves for each of his 4 children

so he is actually buying 8 hats and 12 scarves.

a hat costs 8.50 and a scarf costs 5.50

so you put it into a equation

8.50(h)+5.50(s) = P     h = hat, s = scarf, P = pay

8.50(8)+5.50(12) = P

68 + 66 = P

P = 134

hope this helps
6 0
3 years ago
May someone explain to me how to do this?
lara31 [8.8K]

Answer:

All you gotta do is go to "desmos" and type in all of the 4 solutions. A, B, C, and D. and see which answer matches the graph

Step-by-step explanation:

4 0
3 years ago
5 Vera is a shop manager. 5 She has this information about the income in her shop for eight weeks this year. Week 1 2. 3 4 5 6 7
Alex

Using the median concept, it is found that it suffered a 11.16% decrease.

<h3>What is the median of a data-set?</h3>

It is the 50th percentile of the data-set, which is the value that separates the lower 50% from the upper 50%.

In this problem, the ordered data-set, in thousands of £, is given by:

{19.4, 39.8, 42.3, 42.5, 45.1, 47.9, 52.4, 53.5}

It has even cardinality, hence the median is the mean of the 8/2 = 4th and 5th terms, so:

M = (42.5 + 45.1)/2 = £43800.

It decreased from £49300 last year. The percentage decrease is the change divided by initial amount and multiplied by 100%, hence:

P = (49300 - 43800)/49300 x 100% = 11.16%.

More can be learned about the median concept at brainly.com/question/25215461

5 0
2 years ago
What’s The answer to this question?
fredd [130]

Answer:

7

Step-by-step explanation:

It is a pattern where you add 3 each time

6 0
4 years ago
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