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Ghella [55]
3 years ago
14

: Write a function "def countWords(string)" that returns a count of all words in an input string represented by the variable 'st

ring'.
Computers and Technology
1 answer:
Zina [86]3 years ago
3 0
We can define a word as a group of characters without a space between them. To find the words of the input string , w can use split(delimiter) which returns a list of strings which had the defined delimiter between them in the input string.

def countWords(string):
words = string.split(" ")
count = len(words)
return count

Here we set the delimiter as the space character, and returned the length of the words list. I split each step into its own line for readability, however the function could be one line:

return len(string.split())

Here, no delimiter is specified. If one isn't given, it will default to split at any whitespace, including space.

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What are the three main elements common to all radio ads?
Mama L [17]
Answer: final notions on frequency, reach, and consistency.



If my answers wrong please tell me :D
5 0
3 years ago
Read 2 more answers
What term refers to a device or software system that collects environmental information and makes independent decisions.
blondinia [14]

Answer: Environment sensing Collector

Explanation:

An environmental monitoring system or collectors is the process which a device uses in monitoring the quality of the environment. These devices or software allows for a realtime monitoring and checking of any parameter required. They are used to monitor and collect data on environmental conditions such as relative humidity, temperature, dew and frost point, differential pressure, pressure, flow, and many more.

6 0
3 years ago
You should process the tokens by taking the first letter of every fifth word,starting with the first word in the file. Convert t
zhenek [66]

Answer:

See explaination

Explanation:

import java.io.File;

import java.io.IOException;

import java.util.Scanner;

import java.util.StringTokenizer;

public class SecretMessage {

public static void main(String[] args)throws IOException

{

File file = new File("secret.txt");

StringBuilder stringBuilder = new StringBuilder();

String str; char ch; int numberOfTokens = 1; // Changed the count to 1 as we already consider first workd as 1

if(file.exists())

{

Scanner inFile = new Scanner(file);

StringTokenizer line = new StringTokenizer(inFile.nextLine()); // Since the secret.txt file has only one line we dont need to loop through the file

ch = line.nextToken().toUpperCase().charAt(0); // Storing the first character of first word to string builder as mentioned in problem

stringBuilder = stringBuilder.append(ch);

while(line.hasMoreTokens()) { // Looping through each token of line read using Scanner.

str= line.nextToken();

numberOfTokens += 1; // Incrementing the numberOfTokens by one.

if(numberOfTokens == 5) { // Checking if it is the fifth word

ch = str.toUpperCase().charAt(0);

stringBuilder = stringBuilder.append(ch);

numberOfTokens =0;

}

}

System.out.println("----Secret Message----"+ stringBuilder);

}

}

}

5 0
3 years ago
Variables set equal to patterns are said to be:_______.
NemiM [27]

Answer:

b. instantiated.

Explanation:

In computer programming, to be instatiated or when variables are instatiated; this simply refers to the acts of making example out of a group variables or a form of template. For example in a situation of class of objects.

Hence, in this case, the correct answer to the question above is the option B, in which Variables set equal to patterns are said to be INSTATIATED

5 0
3 years ago
How are air masses and fronts the same. And how are they different. ​
Sergeu [11.5K]

Answer:

Air Masses are warmer air while front is an area of cold air that comes out warm. Font is a place where two of the air masses meet. Font is the borderline between an air mass.

Let me know if I was correct? Hope I could be of help!

Explanation:

7 0
3 years ago
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