The cofactors of each entry in the first row of the matrix are
Ac_11 = -13
Ac_12 = 44
Ac_13 = 27
We have to determine the cofactors of each entry in the first row of the matrix.
Therefore the cofactors of each entry in the first row of the matrix are
Ac_11 = -13
Ac_12 = 44
Ac_13 = 27.
A set of numbers is arranged in rows and columns so as to form a rectangular array. The numbers are called the elements, or entries, of the matrix.
Machines had to find a way to cut themselves off from the truth in order to understand humans. Neo's sole purpose in the Matrix is to prevent machines from evolving into dinosaurs.
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Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So



has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
The answer is x=3 Your Welcome!
Answer:
74.25feet
Step-by-step explanation:
Given the scale of a model train expressed as;
1in = 13.5feet
We are to express length of 5.5in in feet
5.5in = x
Divide both expressions
1/5.5 = 13.5/x
Cross multiply
1×x = 5.5× 13.5
x = 74.25feet
Hence the actual length of the car in feet is 74.25feet