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Ivanshal [37]
3 years ago
9

A box contains 15 lbs.of books. There are 20 books in the box. How much does each book weigh?

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

0.75 lbs.

Step-by-step explanation:

Okay, this one is more simple. To find the weight of each book, You have to solve this division problem:

15/20

If you divided it the other way around, you would be saying each book weighed 1.33 pounds. That wouldn't be correct because then you would have over 20 lbs. of books, when you only have 15.

So, the answer is 0.75 pounds.

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Scorpion4ik [409]

Answer:

14..........................

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3 years ago
Rewrite the form In exponential form:<br> Log100 = x
andrey2020 [161]

Answer:

10^x=100

Step-by-step explanation:

You know how subtraction is the <em>opposite of addition </em>and division is the <em>opposite of multiplication</em>? A logarithm is the <em>opposite of an exponent</em>. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.

We know that 3^2=9; as a logarithm, the <em>exponent</em> gets moved to its own side of the equation, and we write the equation like this: \log_3{9}=2, which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."

One historical quirk: because we use the decimal system, it's assumed that an expression like \log1000 uses <em>base 10</em>, and you'd interpret it as "What power do I raise 10 to to get 1000?"

The expression \log100=x means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is 10^x=100.

(If we wanted to, we could also solve this: 10^2=100, so \log100=2)

6 0
2 years ago
Lucy si thinking of a Numbers. The number is greater than two hundred twenty-five. Her number is less than 2 hundreds,2 tens, an
VikaD [51]
226 i believe, if not then idk
8 0
3 years ago
For which positive integer values of $k$ does $kx^2+20x+k=0$ have rational solutions? Express your answers separated by commas a
Musya8 [376]

Answer:

-10,10

Step-by-step explanation:

The given quadratic equation is

k {x}^{2}  + 20x + k = 0

The discriminant of this equation is given by;

D =  {b}^{2}  - 4ac

where a=k, b=20, c=k

For rational solutions, the discriminant must be zero.

{20}^{2}  - 4 \times k \times k = 0

Simplify to get:

400 - 4  {k}^{2}  = 0

This implies that:

400  = 4  {k}^{2}

100 =  {k}^{2}

Take square root to get:

k =   \pm\sqrt{100}

k =  \pm10

k =  - 10 \: or \: k = 10

3 0
2 years ago
PLEASE HELP ME KIND SOUL! Look at the picture below to understand everything
ruslelena [56]

Answer:

Yes, it is 368.24, because you cannot use a digit more than once.

Step-by-step explanation:

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