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Elena L [17]
3 years ago
14

Please help me!!! I need help on the bottom part of number 11. Please help me

Mathematics
1 answer:
UNO [17]3 years ago
8 0
Each side is 100 cubic millimeters :D



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10. (a) Consider the following matrices: A = ( 2 ) B = (3) and C = (-3) w = Find the det(A). [1] (ii) Is the matrix A singular?
Viefleur [7K]

i) We have to find the determinant of A.

We can do this as:

\det(A)=|\begin{bmatrix}{3} & {6} \\ {1} & {-2}\end{bmatrix}|=3*(-2)-6*1=-6-6=-12

ii) We have to find if the matrix A is singular.

Singular matrix have determinant equal to 0.

This is not the case for A, as its determinant is -12. Then, A is not a singular matrix.

iii) We have to find the values of x and y so that AB = C.

We have to write the matrix multiplication and we will obtain a system of linear equations:

We can now solve the system of equations by adding 3 times the second equation to the first equation:

\begin{gathered} 3(x-2y)+(3x+6y)=3(-3)+(-3) \\ 3x-6y+3x+6y=-9-3 \\ 6x+0y=-12 \\ x=\frac{-12}{6} \\ x=-2 \end{gathered}

We can now use the second equation to find the value of y:

\begin{gathered} x-2y=-3 \\ x+3=2y \\ y=\frac{x+3}{2} \\ y=\frac{-2+3}{2} \\ y=\frac{1}{2} \end{gathered}

The values are x = -2 and y = 1/2.

iv) When we want to multiply two matrices, the required condition is that the number of columns of the matrix on the left is equal the number of rows of the matrix on the right.

In the case of A(2x2) and B(2x1), when we do A*B this condition is satisfied.

But when we try to multiply BA, the number of columns of B is not equal to the number of rows of A, so the matrix mulitplication is not possible.

Answer:

i) det(A) = -12

ii) A is not singular because singular matrices have determinant equal to zero.

iii) x = -2 and y = 1/2.

iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.

6 0
1 year ago
annie needs a piece of cardboard with an area of 180 square centimeters. the length of the cardboard should be 7 centimeters les
baherus [9]
The length is 20 and the width is 9. Hope this helps.
8 0
3 years ago
HELPPPPP!!!!!!!!!!!! will mark brainliest!! :D
allsm [11]

Solving the equation we get:

1\frac{4}{9}-\frac{3}{4}=\frac{52}{\textbf{36}}-\frac{27}{\textbf{36}}=\frac{\textbf{25}}{\textbf{36}}

Step-by-step explanation:

We need to solve the equation: 1\frac{4}{9}-\frac{3}{4}

Solving:

1\frac{4}{9}-\frac{3}{4}

\frac{13}{9}-\frac{3}{4}

Taking LCM of 9 and 4 we get 36

\frac{13*4}{36}-\frac{3*9}{36}

\frac{52}{36}-\frac{27}{36}

\frac{52-27}{36}

\frac{25}{36}

So, solving the equation  1\frac{4}{9}-\frac{3}{4} we get \frac{25}{36}

In the first blank, in denominators we get 36 and in the second black we get \frac{25}{36}

So, answer is:

1\frac{4}{9}-\frac{3}{4}=\frac{52}{\textbf{36}}-\frac{27}{\textbf{36}}=\frac{\textbf{25}}{\textbf{36}}

Keywords: Solving Fractions

Learn more about Solving Fractions at:

  • brainly.com/question/2456302
  • brainly.com/question/4390083
  • brainly.com/question/2456302

#learnwithBrainly

3 0
3 years ago
Evaluate 32 + (7 − 2) ⋅ 4 − 6 over 3.
tia_tia [17]
<span>Parenthesis statements are evaluated first such that 7-2 Is 5.
From left to right, multiplication and division are evaluated: 5×4=20 6/3 =2
Finally addition and subtraction equating finally to: 32 + 20 - 2 = 50</span>
7 0
3 years ago
If h(x)=0 then does h(<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle
PSYCHO15rus [73]

Answer:

true

Step-by-step explanation:

8 0
3 years ago
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