Answer:
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hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =4 and b = -1 (Center at the origin)
r = AP.... P(0.1)
r² = (AP)²
r² = (4-0)² +(-1-1)² = 16+4=20
an equation of the circle that satisfies the stated conditions.
Center at A(4,-1), passing through P(0, 1) is : </span></span>(x-4)² +(y+1)² = 20
1. System B from System A by replacing one equation with itself where the same quantity is added to both sides
2. Yes, both system A and system B are equivalent and therefore has the same solution
<h3>How to prove the statements</h3>
System A
x − 4y= 1
5x + 6y= −5
System B
x = 1+4y
5x + 6y= −5
1. System B can be gotten from system A by
from the first equation of A
x − 4y= 1
Make 'x' subject of formula
x = 1 + 4y
This makes it equal to tat of system B
Thus, replacing one equation with itself where the same quantity is added to both sides
2. System A
x = 1 + 4y
5x + 6y= −5
System B
x = 1 + 4y
5x + 6y= −5
From the above equations, we can see that both system A and system B are equivalent and therefore has the same solution.
Learn more about linear equations here:
brainly.com/question/4074386
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Answer:
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