Answer:
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Step-by-step explanation:
Help answer the question in the picture please.
2 answers:
Answer:
<h3>boang ka bshshsiiaiajsh</h3><h3><em><u><em><u>e</u></em><em><u>s</u></em><em><u>t</u></em><em><u>g</u></em><em><u>s</u></em><em><u>y</u></em><em><u>e</u></em><em><u>u</u></em><em><u>u</u></em><em><u>r</u></em><em><u>j</u></em><em><u>b</u></em><em><u>t</u></em><em><u>b</u></em><em><u> </u></em><em><u>r</u></em><em><u>b</u></em><em><u>r</u></em><em><u>d</u></em>
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Answer:
Step-by-step explanation:
to solve this problem we can use the Pythagorean theorem
UT and TL are the legs, while LU is the hypotenuse
We have to find LU so we can proceed like this
x^2 + (x+1)^2 = LU^2
x^2 + x^2 + 1 + 2x = LU^2
2x^2 + 2x + 1 = LU^2
LU = +/-
we have to take only the positive value because a length can’t be negative.
2x^2 + 2x + 1 is positive for every value of x, so the final answer is
Answer:
Explanation:
Since, there are two possible outcomes for every toss (head or tail), the sample space for<em> a coin tossed 8 times</em> is 2×2×2×2×2×2×2×2 = 2⁸ = 256.
<em>Landing on heads all 8 times</em> is just one of the possible outcomes: HHHHHHHH ⇒ 1.
Hence, the <em>probability </em>is calculated from its own definition:
Probability = number of favorable outcomes / number of possible outcomes