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3 years ago

Pls help, I’m kinda in middle of a quiz atm

Mathematics

2 answers:

bixtya [17]3 years ago

6 0

Answer:

X=40

Step-by-step explanation:

60=2x-20

80=2x

x=40

Basile [38]3 years ago

4 0

x = 40

I hope this helps :))

You might be interested in

When graphed, which function has a horizontal asymptote at 4?

galben [10]

Answer:

Correct answer: C. f(x) = 2(3)x + 4

(please note we changed the expression of the function to exponential form which we believe is the correct form of the question)

Step-by-step explanation:

Horizontal Asymptote

The graph of a function is said to have a horizontal asymptote at y=a if one or both the following limits exist

$\lim\limits_{x \rightarrow \infty}f(x)=a$

$\lim\limits_{x \rightarrow -\infty}f(x)=a$

The horizontal asymptotes are horizontal lines to which the function tends when x increases or decreases without limits.

Let's analyze each one of the options provided:

A. f(x) = 2x -4

$\lim\limits_{x \rightarrow \infty}(2x-4)=+\infty$

$\lim\limits_{x \rightarrow -\infty}(2x-4)=-\infty$

No horizontal asymptote

B. f(x) = -3x + 4

$\lim\limits_{x \rightarrow \infty}(-3x+4)=-\infty$

$\lim\limits_{x \rightarrow -\infty}(-3x+4)=\infty$

No horizontal asymptote

C. f(x) = 2\cdot 3^x + 4

$\lim\limits_{x \rightarrow \infty}(2\cdot 3^x + 4)=2\cdot 3^\infty + 4=\infty$

$\lim\limits_{x \rightarrow \infty}(2\cdot 3^x + 4)=2\cdot 3^{-\infty} + 4=0+4=4$

This function has a horizontal asymptote at y=4

D. 3\cdot 2^x -4

$\lim\limits_{x \rightarrow \infty}(3\cdot 2^x - 4)=3\cdot 2^\infty - 4=\infty$

$\lim\limits_{x \rightarrow \infty}(3\cdot 2^x- 4)=3\cdot 2^{-\infty} - 4=0-4=-4$

This function has a horizontal asymptote at y=-4

Correct answer: C.

8 0

3 years ago

The area of the regular hexagon is 10.4in

dsp73

Poooooooooooooooooooooooooooooop

6 0

3 years ago

3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r

vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$ .

Slope-intercept form of equation is given as $y=-2 x-2$ .

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$y_{1}=2 \text {. }$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$

Hence, slope-intercept form of equation is given as y=-2x-2.

7 0

2 years ago

State the slope and the y-intercept for the graph of the equation. y= -2

kotegsom [21]

Answer: 0; -2

Step-by-step explanation:

Data: y-intercept=x and slope=x

Equation=y=-2

Only step, Point out the y-intercept and slope

-2=y-intercept

0=slope

Reason: Since there is no visible slope, the placeholder would be 0 therefore the slope would be 0, -2 is the only number left so that means the only number that can be y-intercept is -2.

That is why the slope is 0 and the y-intercept is -2

I hope this helps!

5 0

2 years ago

Sofia's grandfather has 18 sacks of candies. There are 348 pieces in each sack of candies. How many candies does Sofia's grandfa

sleet_krkn [62]

Answer:

18 x 348 = 6,264.

Sofia's grandfather has 6,264 candies in total.

5 0

3 years ago

Read 2 more answers