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pickupchik [31]
3 years ago
5

When graphed, which function has a horizontal asymptote at 4?

Mathematics
1 answer:
galben [10]3 years ago
8 0

Answer:

<em>Correct answer: C. f(x) = 2(3)x + 4</em>

<u><em>(please note we changed the expression of the function to exponential form which we believe is the correct form of the question)</em></u>

Step-by-step explanation:

<u>Horizontal Asymptote</u>

The graph of a function is said to have a horizontal asymptote at y=a if one or both the following limits exist

\lim\limits_{x \rightarrow \infty}f(x)=a

\lim\limits_{x \rightarrow -\infty}f(x)=a

The horizontal asymptotes are horizontal lines to which the function tends when x increases or decreases without limits.

Let's analyze each one of the options provided:

A.  f(x) = 2x -4

\lim\limits_{x \rightarrow \infty}(2x-4)=+\infty

\lim\limits_{x \rightarrow -\infty}(2x-4)=-\infty

No horizontal asymptote

B.  f(x) = -3x + 4

\lim\limits_{x \rightarrow \infty}(-3x+4)=-\infty

\lim\limits_{x \rightarrow -\infty}(-3x+4)=\infty

No horizontal asymptote

C. f(x) = 2\cdot 3^x + 4

\lim\limits_{x \rightarrow \infty}(2\cdot 3^x + 4)=2\cdot 3^\infty + 4=\infty

\lim\limits_{x \rightarrow \infty}(2\cdot 3^x + 4)=2\cdot 3^{-\infty} + 4=0+4=4

This function has a horizontal asymptote at y=4

D. 3\cdot 2^x -4

\lim\limits_{x \rightarrow \infty}(3\cdot 2^x - 4)=3\cdot 2^\infty - 4=\infty

\lim\limits_{x \rightarrow \infty}(3\cdot 2^x- 4)=3\cdot 2^{-\infty} - 4=0-4=-4

This function has a horizontal asymptote at y=-4

Correct answer: C.

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monitta
I hope everythink is clearly :) If not just ask :)


answer for your question is starting when x^2-14x-95=0. Just Ignore this above this.

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2 years ago
A trapezoid has bases of lengths 13 cm and 17 cm. The
Vedmedyk [2.9K]

Answer:

135 cm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h(a + b)

where h is the height and a, b the parallel bases

Here h = 9, a = 13 and b = 17 , thus

A = \frac{1}{2} × 9 × (13 + 17)

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3 years ago
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HACTEHA [7]

Answer:

A 4/5 × 10 1/2 =8.4

B 2 1/2 × 16/5 =8

C 3 2/3 × 2 1/2 = 330/36 = 9.1666

D 20/3 × 9/10 =6

C IS THE GREATEST because 9.166 is greater than 8.4, 8 and 6

7 0
2 years ago
PLEASE HELP MEE!! SHOW YOUR WORK PLS
sleet_krkn [62]

Answer:

(8, -8)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = x - 16

5y = 2x - 56

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in <em>y</em>:                                                                                                5(x - 16) = 2x - 56
  2. Distribute 5:                                                                                                     5x - 80 = 2x - 56
  3. [Subtraction Property of Equality] Subtract 2x on both sides:                     3x - 80 = -56
  4. [Addition Property of Equality] Add 80 on both sides:                                3x = 24
  5. [Division Property of Equality] Divide 3 on both sides:                                x = 8

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                                                                               y = x - 16
  2. Substitute in <em>x</em>:                                                                                                y = 8 - 16
  3. Subtract:                                                                                                          y = -8
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Blababa [14]

Answer:

A

Step-by-step explanation:

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