Answer:
<h2>1- sec (

) + tan (x) 2</h2>
Step-by-step explanation:
we can divide the composite shape into on quadrilateral and triangle as shown in the diagram. since the line that joins the two shape is parallel to the base AB, the angle DEC is 85°.The angle CEA is 180°- angle DEC = 180-85=95. Angle BCE is sum of angle CEA, ABC and EAB subtracted from360°= 360°-(95+95+85)=85°. Angle DCE is 120°- ECB=35°. So, angle CDE = 180°-(35°+85°)= 60°. For reference see the diagram.
Answer: No. Kyle will arrive late
Step-by-step explanation:
The only speed limit is 50 miles per hour.
Kyle must cover 130 miles.
His travel time = 130/50 = 2.6
2 hours + (0.6 of 60 minutes )
2 hours + (36 minutes)
i.e kyle needs 2hours 36 minutes to cover 130 miles
And since the baseball starts in 2 hours, kyle will be late. Thus, the answer is No
Check the picture below.
to get the equation of any straight line, we simply need two points off of it, so let's use those in the picture

