Question

A rectangular room is 4 meters longer than it is wide, and its perimeter is 28 meters. Find the dimension of the room.

Answer 1

Answer: The width of the room = 5 meters

The length of the room = 9 meters

Step-by-step explanation:

Let the w denotes the width of the room , then length of the room will be :-

$\text{length}=4+w$

The formula of perimeter of rectangle :-

$\text{Perimeter}=2(l+w)\\\\\Rightarrow\ 28=2(4+w+w)\\\\\Rightarrow\ 28=2(4+2w)\\\\\Rightarrow\ 28 =8+4w\\\\\Rightarrow\ 4w=20\\\\\Rightarrow\ w=5$

Hence, The width of the room = 5 meters

The length of the room = 5+4 = 9 meters

Answer 2

Well you would start by drawing a rectangle. Label one side W and One side (W+4) then you would set up this equation

2(W+4)+2W=28 
2W+8+2W=28
4W+8=28
4W=20
W=5

So that's the width then you will plug it into (W+4) 
(5+4)=9

So you have a room that has a length of 9 and a width of 4