Answer and Explanation:
The line seems to pass trough the points (0,6) and (-3,4).
Slope is:
The slope of the line should be .
Hello here is a solution :
x²-8y-6x+y²=4....(1)
A)
x²-6x = x²-2(3)x+9-9
= x²-2(3)x+3²-9
x²-6x =(x-3)² -9
B)
y²-8y = y²-2(4)y +4²-16
y²-8y = (y-4)²-16
C)
in (1) :
(x-3)² -9 +(y-4)²-16 = 4
(x-3)² +(y-4)² = 29 ...<span>is the standard form of the equation
</span> <span>Select answer 1 :
</span><span>A: 3
B: 4
C: (x−3)2+(y−4)2=29</span>
Plug in "8i + 15j + k" for "f", and "2i – 5j + 9k" for "e"
3(8i + 15j + k) - 2(2i – 5j + 9k)
Distribute 3 to (8i + 15j + k) & - 2 to (2i – 5j + 9k)
3(8i + 15j + k) = 24i + 45j + 3k
-2(2i - 5j + 9k) = -4i + 10j - 18k
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Simplify. Combine like terms
24i - 4i + 45j + 10j + 3k - 18k
(24i - 4i) + (45j + 10j) + (3k - 18k)
20i + 55j - 15k is your answer, or (C)
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hope this helps
Answer:
A≈18.38
Step-by-step explanation:
Solve for area
Shape: Parallelogram
Formula: Base*Height
5.25*3.5=18.375
Round answer
Hope this helps.
Answer:
∠ C = 58°
Step-by-step explanation:
DB is a perpendicular bisector , so
∠ ADC = 2 × 32° = 64°
Since AD = CD then Δ ACD is isosceles with the base angle congruent , then
∠ C = = = 58°