Answer:
C, 38°
Step-by-step explanation:
ray UW is the angle bisector of ∠VUT
--> m∠VUW = m∠WUT = 1/2 m∠VUT
<=> 4x + 6 = 6x - 10
<=> 6 + 10 = 6x - 4x
<=> 2x = 16
<=> x = 8
So, the measure of m∠WUT is: 6x - 10 = 6 . 8 - 10 = 48 - 10 = 38°
Simplifying
9x + -3(x + 8) = 6x + -24
Reorder the terms:
9x + -3(8 + x) = 6x + -24
9x + (8 * -3 + x * -3) = 6x + -24
9x + (-24 + -3x) = 6x + -24
Reorder the terms:
-24 + 9x + -3x = 6x + -24
Combine like terms: 9x + -3x = 6x
-24 + 6x = 6x + -24
Reorder the terms:
-24 + 6x = -24 + 6x
Add '24' to each side of the equation.
-24 + 24 + 6x = -24 + 24 + 6x
Combine like terms: -24 + 24 = 0
0 + 6x = -24 + 24 + 6x
6x = -24 + 24 + 6x
Combine like terms: -24 + 24 = 0
6x = 0 + 6x
6x = 6x
Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x
Combine like terms: 6x + -6x = 0
0 = 6x + -6x
Combine like terms: 6x + -6x = 0
0 = 0
Solving
0 = 0
Exact Form:
-1/3
Decimal Form:
-0.3 (with a line over the 3)
Answer:
The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎
Step-by-step explanation:
For a reflection across the line y = -x, we have, (x, y) → (y, x)
Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x
The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)
Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'
Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎
1)28
2)21
3)26
4)21
Now you have to add the ft in mi cm